如何在Java中双击或执行该路径以获取正确的路径？

Question

My java jar is installed in c:\\program files<i do not know>\\i do not know\\here.jar . When the user execute my application.

I always get c:\\uesrs\\\\here.jar and its failing.

String Windows7HomeEditionProgramFileDirectroyStruct = System.getProperty("user.dir");

How can i get the correct path where it was double clicked or executed from?

Details (tested both answer but none is saying where the jar is located):

Try 1)

new File(".").getAbsolutePath();
or

new File(".").getCanonicalPath();

C:\Users\sun>java -jar "C:\Users\sun\Documents\NetBeansProjects\JavaApplication1
\dist\JavaApplication1.jar"
C:\Users\sun\.

Try 2)

ClassLoader.getSystemClassLoader().getResource(".").getPath();

C:\Users\sun>java -jar "C:\Users\sun\Documents\NetBeansProjects\JavaApplication1
\dist\JavaApplication1.jar"
Exception in thread "main" java.lang.NullPointerException
        at javaapplication1.JavaApplication1.main(JavaApplication1.java:18)

Follow up:

String test = JavaApplication1.class.getProtectionDomain().getCodeSource().getLocation().getPath();

C:\>java -jar "C:\Users\sun\Documents\NetBeansProjects\JavaApplication1\dist\Jav
aApplication1.jar"
/C:/Users/sun/Documents/NetBeansProjects/JavaApplication1/dist/JavaApplication1.
jar

Answer 1

You can get the current directory like that:

String path = new File(".").getAbsolutePath();

What you get using "user.dir" is the user directory.

Answer 2

Using user.dir will always give you the Users directory in Windows.

Try this:

ClassLoader.getSystemClassLoader().getResource(".").getPath();

Answer 3

The "user.dir" system property will return the working directory for the JAR file. The same is true for Binyamin's answer.

You are looking for the directory that contains the executing JAR file. A similar question was posed in this thread , the answer may help you.