寻找支持UTF8的格式化函数，如printf（）等

Question

I discovered an interesting problem when processing UTF-8 strings containing non-ASCII chars with C standard library formatting functions like sprintf():

The functions of the printf() family are not aware of utf-8 and process everything based on the number of bytes, not chars. Therefore the formatting is incorrect.

Simple example:

#include <stdio.h>

int main(int argc, char *argv[])
{
    const char* testMsg = "Tääääßt";
    char buf[1024];
    int len;

    sprintf(buf, "|%7.7s|", testMsg);
    len = strlen(buf);
    printf("Result=\"%s\", len=%d", buf, len);

    return 0;
}

The result is:

 Result="|Täää|", len=7

Most probably some of you will recommand to convert the application from char to wchar_t and use fwprintf(), etc., but that's absolutely impossible because of huge existing applications. I could imagine writing a wrapper that uses these functions internally, but this would be tricky and very inefficient.

So the best solution would be a UTF-8-aware replacement for the formatting functions of the Standard C Library.

Currently I'm working on QNX 6.4, but replies for other operating systems. eg Linux, are also very welcome.

Answer 1

Well, once you ask printf to do intelligent padding of Unicode characters, you run into major problems. As they say,

w͢͢͝h͡o͢͡ ̸͢k̵͟n̴͘ǫw̸̛s͘ ̀́w͘͢ḩ̵a҉̡͢t ̧̕h́o̵r͏̵rors̡ ̶͡͠lį̶e͟͟ ̶͝in͢ ͏t̕h̷̡͟e ͟͟d̛a͜r̕͡k̢̨ ͡h̴e͏a̷̢̡rt́͏ ̴̷͠ò̵̶f̸ u̧͘ní̛͜c͢͏o̷͏d̸͢e̡͝?͞

• How many Unicode characters are in Tääääßt ? Well, it could be anywhere from 7 to 11, depending on how it's encoded. Each ä can be written as U+00E4, which is one character, or it could be written as U+0061 U+0308, which is two characters. So your next hope is to count grapheme clusters. (No, normalization won't make the problem go away.)

• But, how wide is a grapheme cluster? Obviously, a is one column wide. U+200B should be zero columns wide, it's a "zero-width" space. Should each ひらがな be two columns wide? They usually are in terminal emulators. What happens when you format ひらがな as 7 columns, do you get "ひらが " , which adds a space, or do you get "ひらが" , which is only 6 columns?

• If you cut something up which mixes RTL and LTR text, should you reset the text direction afterwards? What are you going to do? (Some terminal emulators, such as Apple's, support a mixture of left-to-right and right-to-left text.)

• What is your goal by truncating text? Are you trying to show the user a string in limited space, or are you trying to write a format that uses fixed-width fields?

Basically, if you want to cut Unicode text into chunks, you shouldn't be doing it with something as simple as printf (or wprintf , which is quite possibly worse). Use LibICU ( website ) to iterate over the breaks you want. Writing a UTF-8 aware version of printf is asking for all sorts of trouble that you don't want.

Answer 2

The following C99 code snippet defines the function u8printf where format specifiers such as %10s yield 10 utf-8 code points, that is characters rather than bytes. Don't forget to set the locale with setlocale(LC_ALL,"") somewhere before this routine is called. This works because the wprintf uses wchar_t internally. You can define u8fprintf and u8sprintf in a similar way. If you want to write this without C99 variable length arrays than a suitable combination of malloc/free is also possible.

int u8printf(char *fmt,...){
    va_list ap;
    va_start(ap,fmt);
        int n=mbstowcs(0,fmt,0);
        if(n==-1) return -1;
        wchar_t wfmt[n+1];
        mbstowcs(wfmt,fmt,n+1);
        for(int m=128;m<=32768;m*=2){
            wchar_t wbuf[m];
            int r=vswprintf(wbuf,m,wfmt,ap);
            if(r!=-1) {
                char buf[m*4];
                wcstombs(buf,wbuf,m*4);
                fputs(buf,stdout);
                return r;
            }
        }
        return -1;
    va_end(ap);
}