在c＃中浮动并加倍

Question

Is it necessary to specify f while initiating a float type variable.

float a =3455.67f;

If I declare and initiate it as

float a = 3455.67;

Then what will happen?

Answer 1

The documentation on float says:

By default, a real numeric literal on the right side of the assignment operator is treated as double . Therefore, to initialize a float variable, use the suffix f or F .

This means that if you do float a = 3455.67; then the compiler will refuse to implicitly convert the double to a float .

Answer 2

By default, a real numeric literal on the right side of the assignment operator is treated as double. Therefore, to initialize a float variable, use the suffix f or F, as in the following example:

float x = 3.5F;

If you do not use the suffix in the previous declaration, you will get a compilation error because you are trying to store a double value into a float variable.

for more details look at msdn

Answer 3

This :

float a = 3455.67;

will not compile. 3455.67 is a double constant and C# will permit you to assign this value to a float variable.

Use:

float f = (float)3455.67;

or you will have to specify the "f" format suffix.