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使用类模板的C ++程序:错误LNK2019

[英]A C++ Program Using Class Template:error LNK2019

I just begin to learn C++ and I am now writing a C++ Program using class template.It realize some easy functions of a queue.But I get an error. 我刚开始学习C ++,现在正在使用类模板编写C ++程序,它实现了一些简单的队列功能,但出现错误。 The program concludes two files:Queue.h and Queue.cpp.Now I post my code. 该程序总结了两个文件:Queue.h和Queue.cpp。现在我发布代码。 Queue.h: Queue.h:

#ifndef QUEUE_H
#define QUEUE_H

#include <iostream>
#include <cstdlib>
using namespace std;

template <class T> class QueueItem;

//define class template Queue
template <class Type>
class Queue{
public:
    Queue():front(0),back(0){}
    ~Queue();

    Type remove();
    void add(const Type&);
    bool is_empty() const{
        return front == 0;
    }

    friend ostream& operator<<(ostream&,const Queue<Type> &);

private:
    QueueItem<Type> *front;
    QueueItem<Type> *back;
};

//define class template QueueItem
template <class Type> 
class QueueItem{
public:
    QueueItem(const Type&t):item(t),next(0){}

    friend class Queue<Type>;

    friend ostream& operator<<(ostream&,const QueueItem<Type>&);
private:
    Type item;
    QueueItem *next;
};

template <class  Type>
Queue<Type>::~Queue()
{
    while(!is_empty())
        remove();
}

template <class Type>
void Queue<Type>::add(const Type &val)
{
    QueueItem<Type> *pt = new QueueItem<Type>(val);
    if (is_empty())
        front = back = pt;
    else
    {
        back ->next = pt;
        back = pt;
    }
}

template <class Type>
Type Queue<Type>::remove()
{
    if (is_empty())
    {
        cerr << "remove() on empty queue!"<<endl;
        exit(-1);
    }
    QueueItem<Type> *pt = front;
    front = front ->next;
    Type retval = pt ->item;
    delete pt;
    return retval;
}

template <class Type>
ostream& operator<<(ostream &os,const Queue<Type> &q)
{
    os << "<";
    QueueItem<Type> *p;
    for (p = q .front;p;p = p ->next)
    {
        os << *p << " ";
    }
    os << ">";

    return os;
}

template <class Type>
ostream& operator<<(ostream &os,const QueueItem<Type> &qi)
{
    os << qi.item;
    return os;
}

#endif

Queue.cpp: Queue.cpp:

#include "Queue.h"
#include <iostream>
using namespace std;

int main()
{
    //Queue<int> *p_qi = new Queue<int>;
    Queue<int> p_qi;
    cout << p_qi <<endl;

    for (int ival = 0;ival < 10;++ival)
    {
        p_qi .add(ival);
    }
    cout << p_qi <<endl;

    int err_cnt = 0;
    for (int ival = 0;ival < 10;++ival)
    {
        int qval = p_qi .remove();
        if (qval != ival)
            ++err_cnt;
    }
    cout << p_qi <<endl;

    if (!err_cnt)
        cout << "!!Queue executed OK!"<<endl;
    else
        cout << "??Queue errors:"<<err_cnt << endl;

    return 0;
}

But I get an error in Visual Studio 2008: 1>Queue.obj : error LNK2019: unresolved external symbol "class std::basic_ostream > & __cdecl operator<<(class std::basic_ostream > &,class Queue const &)" (??6@YAAAV?$basic_ostream@DU?$char_traits@D@std@@@std@@AAV01@ABV?$Queue@H@@@Z),the symbolic is referenced in function _main 1>G:\\CPPPrimer\\Queue\\Debug\\Queue.exe : fatal error LNK1120: a unresolved external symbol 但是我在Visual Studio 2008中遇到错误:1> Queue.obj:错误LNK2019:未解析的外部符号“类std :: basic_ostream>&__cdecl运算符<<(类std :: basic_ostream>&,类队列const&)”( 6 @ YAAAV?$ basic_ostream @ DU?$ char_traits @ D @ std @@@ std @@ AAV01 @ ABV?$ Queue @ H @@@ Z),符号在函数_main 1> G:\\ CPPPrimer中引用\\ Queue \\ Debug \\ Queue.exe:致命错误LNK1120:无法解析的外部符号

Could anyone tell me why? 谁能告诉我为什么? Thanks a lot. 非常感谢。

I have resolved my problems.This is my code that runs on Visual Studio 2008 correctly: 我已经解决了问题。这是我在Visual Studio 2008上正确运行的代码:

#include <iostream>
#include <cstdlib>
using namespace std;

template <class Type> class QueueItem;

//类模板Queue的定义
template <class Type>
class Queue{
public:
    Queue():front(0),back(0){}
    ~Queue();

    Type remove();
    void add(const Type&);
    bool is_empty() const{
        return front == 0;
    }
    //将输出符号声明为函数模板
    template <class T>
    friend ostream& operator<<(ostream&,const Queue<T> &);

private:
    QueueItem<Type> *front;
    QueueItem<Type> *back;
};

//类模板QueueItem的定义
template <class Type> 
class QueueItem{
public:
    QueueItem(const Type&t):item(t),next(0){}

    friend class Queue<Type>;

    //将输出符号声明为函数模板
    template <class T>
    friend ostream& operator<<(ostream&,const QueueItem<T>&);

private:
    Type item;
public:
    QueueItem *next;
};


template <class  Type>
Queue<Type>::~Queue()
{
    while(!is_empty())
        remove();
}

template <class Type>
void Queue<Type>::add(const Type &val)
{
    QueueItem<Type> *pt = new QueueItem<Type>(val);
    if (is_empty())
        front = back = pt;
    else
    {
        back ->next = pt;
        back = pt;
    }
}

template <class Type>
Type Queue<Type>::remove()
{
    if (is_empty())
    {
        cerr << "remove() on empty queue!"<<endl;
        exit(-1);
    }
    QueueItem<Type> *pt = front;
    front = front ->next;
    Type retval = pt ->item;
    delete pt;
    return retval;
}

template <class Type>
ostream& operator<<(ostream &os,const Queue<Type> &q)
{
    os << "<";
    QueueItem<Type> *p;
    for (p = q .front;p;p = p ->next)
    {
        os << *p << " ";
    }
    os << ">";

    return os;
}

template <class Type>
ostream& operator<<(ostream &os,const QueueItem<Type> &qi)
{
    os << qi.item;
    return os;
}

int main()
{
    //Queue<int> *p_qi = new Queue<int>;
    //ostream& operator<<(ostream &os,const Queue<int>&);
    //ostream& operator<<(ostream &os,const QueueItem<int>&);
    Queue<int> p_qi;
    cout << p_qi <<endl;

    for (int ival = 0;ival < 10;++ival)
    {
        p_qi.add(ival);
    }
    cout << p_qi <<endl;

    int err_cnt = 0;
    for (int ival = 0;ival < 10;++ival)
    {
        int qval = p_qi .remove();
        if (qval != ival)
            ++err_cnt;
    }
    cout << p_qi <<endl;

    if (!err_cnt)
        cout << "!!Queue executed OK!"<<endl;
    else
        cout << "??Queue errors:"<<err_cnt << endl;

    return 0;
}

You need to declare your operators first, as such : 您需要首先声明您的运算符,如下所示:

template <typename Type> class Queue;
template <typename Type> class QueueItem;

template <typename Type>
ostream& operator<<(ostream &os,const Queue<Type> &q);

template <typename Type>
ostream& operator<<(ostream &os,const QueueItem<Type> &qi);

And the friend declarations need the template parameter : 并且朋友声明需要template参数:

friend ostream& operator<< <Type>(ostream&,const Queue<Type> &);
friend ostream& operator<< <Type>(ostream&,const QueueItem<Type> &);

This compiles, link and run under gcc and clang. 这将在gcc和clang下进行编译,链接和运行。 Btw, QueueItem needs to have both operators as friend since the code for printing a queue also uses QueueItem members. 顺便说一句,因为打印队列的代码也使用QueueItem成员,所以QueueItem需要同时拥有两个运算符。 On a personal note, I would suggest implementing const accessors and get rid of friends altogther. 就个人而言,我建议实现const访问器,并彻底摆脱朋友。

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