方法1可以将kwargs传递给方法2吗？

Question

I want kwargs to have the same exact contents in method2 as whatever gets passed into method1. In this case "foo" is passed into method1 but I want to pass in any arbitrary values and see them in kwargs in both method1 and method2. Is there something I need to do differently with how I call method2?

def method1(*args,**kwargs):

    if "foo" in kwargs:
        print("method1 has foo in kwargs")

    # I need to do something different here
    method2(kwargs=kwargs)

def method2(*args,**kwargs):

    if "foo" in kwargs:
        # I want this to be true
        print("method2 has foo in kwargs")

method1(foo=10)

Output:

method1 has foo in kwargs

Desired output:

method1 has foo in kwargs
method2 has foo in kwargs

Let me know if I need to clarify what I'm asking, or if this is not possible.

Answer 1

关键字扩展。

method2(**kwargs)

Answer 2

def method1(*args,**kwargs):
    if "foo" in kwargs:
        print("method1 has foo in kwargs")

    method2(**kwargs)

Answer 3

It's called unpacking argument lists. The python.org doc is here . In your example, you would implement it like this.

def method1(*args,**kwargs):      
    if "foo" in kwargs:         
        print("method1 has foo in kwargs")      

    # I need to do something different here     
    method2(**kwargs) #Notice the **kwargs.  

def method2(*args,**kwargs):      
    if "foo" in kwargs:         # I want this to be true         
        print("method2 has foo in kwargs")  

method1(foo=10)