将指针传递给函数时出现“ expected primary-expression before”错误

Question

I'm currently working on code which utilizes an external library and here is part of what is given in the library:

typedef void (*func_start_t) (void *);
extern int create(func_start_t func, void *a);

I'm trying to call this with the following line of code (where foo is another function):

create(func_start_t foo, *args);

However I keep getting an erro expected primary-expression before foo . What am I doing wrong?

Answer 1

You are doing something wrong. The func_start_t in the call to the function is totally unnecessary (and incorrect). You should just write:

create(foo, *args); //Assuming `args` is a pointer to a pointer

Answer 2

Just call this:

create(foo, *args);

I'm assuming foo is a function defined as:

void foo(void*) {/*....*/}