除了最后一个w preg_replace之外，删除逗号

Question

My head is spinning, I tried to do this on my own, but cant figure it out. so once again I will turn to your guys knowledge.

These all are my possible my strings:

My head is spinning with, pregreplace
My head is spinning, with, pregreplace
My head is, spinning, with, pregreplace
My head, is, spinning, with, pregreplace

(Notice commas in above strings)

I want to have all "preg-replaced" / "string-replaced" with only one comma at the end.(Just like displayed on first example)

My head is spinning with, pregreplace

Thanks in advance ;)

Answer 1

You can use a "positive lookahead" like this:

,(?=.*,)

The lookahead is the part in parens. It basically says "only replace this comma if there's another comma later in the string.

The code would look like this:

echo preg_replace('/,(?=.*,)/', '', $str);

I tested this with RegexBuddy to confirm it works:

Answer 2

preg_replace( '/,/', '', $my_string, preg_match_all( '/,/', $my_string) - 1);

以上应该做你需要的。