如何查找和计算与给定字符串匹配的文件数？

Question

I want to find and count all the files on my system that begin with some string, say "foo", using only one line in bash.

I'm new to bash so I'd like to avoid scripting if possible - how can I do this using only simple bash commands and maybe piping in just one line?

So far I've been using find / -name foo* . This returns the list of files, but I don't know what to add to actually count the files.

Answer 1

You can use

find / -type f -name 'foo*' | wc -l

• Use the single-quotes to prevent the shell from expanding the asterisk.
• Use -type f to include only files (not links or directories).
• wc -l means "word count, lines only." Since find will list one file per line, this returns the number of files it found.

Answer 2

find / -name foo* | wc -l find / -name foo* | wc -l should do it. Here is a link to man wc . wc -l counts the number of lines

Answer 3

你可以把它管道到wc

find / -name foo * | wc -l