cmd命令转到打开批处理文件的子目录

Question

So that title was confusing. Let me tell you my needs: I'm wanting to open a batch file that is located in c:\\documents\\test\\

in this batch file i'm wanting to collect the names in c:\\documents\\test\\data and convert it to a text file.

Now the easy way to do this would be:

CD c:\documents\test\data
dir/b/o:n > names.txt

but my issue is that i want to move the folder "\\test" around and always be able to call on the names in the "\\data" file.

Therefore this is what i really need:

CD [variable that says current location] + "\data"

but i dont know how to do this. Please explain your answers thanks.

Answer 1

%~dp0是批处理文件的位置（运行FOR /?了解更多信息）

Answer 2

the . character represents the current working directory... does

cd .\data

do what you need?

edit:

So I see no one really answered your issue. Based on your current edit you would want to define a windows environment variable that held the path to wherever your data folder is, and when you move the folder part of that process would need to update the environment variable so your batch script can find it appropriately.

so if you moved your data folder to C:\\archive\\test\\data you would need some process to call the command line with

SET BATCH_ARCHIVE_PATH="C:\archive\test"

then in your batch script you would do something like:

CD "%BATCH_ARCHIVE_PATH%\data"
dir/b/o:n > names.txt