jQuery-删除所有行，如果该行的第一个td没有具有给定值的id

Question

I have a table with many rows. from which i want to delete all the rows except the row, of which first td has a given id.

i am in half way

 <tr>
   <td id="1" class="td_link" onclick="viewPointDetails(1)">Barrackpur</td>
   <td class="td_link" id="11" class="edit_client" onclick="editPoint(1)">India</td>
 </tr>


 <tr>
   <td id="2" class="td_link" onclick="viewPointDetails(2)">Madiwala</td>
   <td class="td_link" id="11" class="edit_client" onclick="editPoint(1)">India</td>
 </tr>

​

and my jquery;

   $('tr').each(function () {   
       if first td does not have given  id say 1  then delete this row.
   });  

my First row is header. so i dont want this to be checked(do not want this row to be deleted).

Answer 1

You should be able to achieve this without the each loop:

$("tr:not(:has(#1))").remove();

This uses the :has selector to return rows which contain an element matching the selector. It uses the :not selector to get the opposite of that (so you end up with all rows that do not contain an element matching the selector), and then uses remove to remove all elements in the matched set.

Answer 2

Try this

$(document).ready(function () {
     $('tr').each(function () {   
      if($(this).find("td:first").attr("id") == 2)
      {
        $(this).remove();
      }
  });
});