使用Java脚本提取部分简单字符串

Question

Let's say I have these strings (each new line being a separate string):

EducationLink
BioLink
InterestsLink

And I wanted to extract the part that's not "Link" using Javascript. How would I do this? The expected results are

Education
Bio
Interests

I tried a Regex, but I'm not very experienced with them, and it failed:

/^ (^Link) $/

Using string functions such as slice() and substr(), I only got the values to the right of the selected text, not to the left as desired.

Thanks for your help.

Answer 1

text = input.replace(/Link(\n|$)/g,"\n");

Answer 2

you can use .replace()

'EducationLink'.replace('Link', ''); //returns Education

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String/replace

The thing is you CAN use regex to do this replace, but being such a simple scenario (unless there is more to it) why would you overcomplicate things?

Answer 3

You would need to put the Link into the end of your RegEx, such as:

^([A-Z]+)Link$

This matches:

• One or more characters between A and Z
• Then the word Link
• Then the end of the string

The part in parentheses will be returned as a group.

Furthermore, if all you need to do is remove the suffix Link , you can use the replace() method in Javascript:

var x = myStr.replace('Link', '');

Answer 4

一种方法是使用String.split（） ^MDN

var txt = 'EducationLink'.split('Link')[0]; // txt == 'Education'

Answer 5

Try This:

<script>

var str = "EducationLink";
index = str.search(/link/i);
str = str.substr(0,index);

</script> 

Answer 6

As others have pointed out, if all the strings end in 'Link', just use a replace. Otherwise, any of these methods will work fine:

var i = 0;
var strings = [
    'EducationLink',
    'BioLink',
    'InterestsLink'
];
var s = '';
var r = /^(.+)Link$/
for (i = 0; i < strings.length; i += 1) {
    s = strings[i];
    //s = s.substring(0, s.indexOf('Link')); //Uncomment for substring
    //s = s.match(r)[1]; //Uncomment for regex
    s = s.replace('Link', '');
    strings[i] = s;
}
console.log(strings);

Copy and paste into a browser console window to run.

To answer your question ("However, why did my RegEx not work?") in a comment on another answer, your RegEx does the following:

/^ (^Link) $/
//Each regex term on own line, commented below
^   //start of string
    //Literal space
(^Link) //Capturing group, string starting with 'Link'.
    //Literal space
$   //end of string

While you can have two "start of string" identifiers in a Regex, there will only ever be one "start of string". The ^ character is only a negation in a character class which is enclosed in square brackets, not curved. If you want to capture a literal caret ( ^ ), put a backslash in front of it ( \\^ ).