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如何在字典理解中使用 if/else?

[英]How can I use if/else in a dictionary comprehension?

Does there exist a way in Python 2.7+ to make something like the following? Python 2.7+ 中是否存在一种方法来制作如下所示的内容?

{ something_if_true if condition else something_if_false for key, value in dict_.items() }

I know you can make anything with just 'if':我知道你可以用'if'做任何事情:

{ something_if_true for key, value in dict_.items() if condition}

You've already got it: A if test else B is a valid Python expression.你已经明白了: A if test else B是一个有效的 Python 表达式。 The only problem with your dict comprehension as shown is that the place for an expression in a dict comprehension must have two expressions, separated by a colon:如图所示,您的 dict 理解的唯一问题是 dict 理解中表达式的位置必须有两个表达式,用冒号分隔:

{ (some_key if condition else default_key):(something_if_true if condition
          else something_if_false) for key, value in dict_.items() }

The final if clause acts as a filter, which is different from having the conditional expression.最后的if子句充当过滤器,这与具有条件表达式不同。

@Marcin's answer covers it all, but just in case someone wants to see an actual example, I add two below: @Marcin 的回答涵盖了所有内容,但以防万一有人想查看实际示例,我在下面添加了两个:

Let's say you have the following dictionary of sets假设您有以下集合字典

d = {'key1': {'a', 'b', 'c'}, 'key2': {'foo', 'bar'}, 'key3': {'so', 'sad'}}

and you want to create a new dictionary whose keys indicate whether the string 'a' is contained in the values or not, you can use并且您想创建一个新字典,其键指示字符串'a'是否包含在值中,您可以使用

dout = {"a_in_values_of_{}".format(k) if 'a' in v else "a_not_in_values_of_{}".format(k): v for k, v in d.items()}

which yields这产生

{'a_in_values_of_key1': {'a', 'b', 'c'},
 'a_not_in_values_of_key2': {'bar', 'foo'},
 'a_not_in_values_of_key3': {'sad', 'so'}}

Now let's suppose you have two dictionaries like this现在让我们假设你有两本这样的字典

d1 = {'bad_key1': {'a', 'b', 'c'}, 'bad_key2': {'foo', 'bar'}, 'bad_key3': {'so', 'sad'}}
d2 = {'good_key1': {'foo', 'bar', 'xyz'}, 'good_key2': {'a', 'b', 'c'}}

and you want to replace the keys in d1 by the keys of d2 if there respective values are identical, you could do并且您想用d2的键替换d1的键,如果各自的值相同,您可以这样做

# here we assume that the values in d2 are unique
# Python 2
dout2 = {d2.keys()[d2.values().index(v1)] if v1 in d2.values() else k1: v1 for k1, v1 in d1.items()}

# Python 3
dout2 = {list(d2.keys())[list(d2.values()).index(v1)] if v1 in d2.values() else k1: v1 for k1, v1 in d1.items()}

which gives这使

{'bad_key2': {'bar', 'foo'},
 'bad_key3': {'sad', 'so'},
 'good_key2': {'a', 'b', 'c'}}

In case you have different conditions to evaluate for keys and values, @Marcin's answer is the way to go.如果您有不同的条件来评估键和值,@Marcin 的答案就是要走的路。

If you have the same condition for keys and values, you're better off with building (key, value)-tuples in a generator-expression feeding into dict() :如果键和值的条件相同,最好在生成器表达式中构建 (key, value)-元组并输入dict()

dict((modify_k(k), modify_v(v)) if condition else (k, v) for k, v in dct.items())

It's easier to read and the condition is only evaluated once per key, value.它更易于阅读,并且每个键值仅对条件进行一次评估。

Example with borrowing @Cleb's dictionary of sets:借用@Cleb 的集合字典的示例:

d = {'key1': {'a', 'b', 'c'}, 'key2': {'foo', 'bar'}, 'key3': {'so', 'sad'}}

Assume you want to suffix only keys with a in its value and you want the value replaced with the length of the set in such a case.假设你想只后缀keysa在其value和你想要的value在这种情况下所设定的长度代替。 Otherwise, the key-value pair should stay unchanged.否则,键值对应保持不变。

dict((f"{k}_a", len(v)) if "a" in v else (k, v) for k, v in d.items())
# {'key1_a': 3, 'key2': {'bar', 'foo'}, 'key3': {'sad', 'so'}}

值得一提的是,If only 语句将 if 放在最后:

{_ for _ in iterable if True}

Another example in using if/else in dictionary comprehension在字典理解中使用 if/else 的另一个例子

I am working on data-entry desktop application for my own office work, and it is common for such data-entry application to get all entries from input widget and dump it into a dictionary for further processing like validation, or editing which we must return selected data from file back to entry widgets, etc.我正在为我自己的办公室工作开发数据输入桌面应用程序,这种数据输入应用程序通常会从输入小部件中获取所有条目并将其转储到字典中以进行进一步处理,例如验证或编辑,我们必须返回从文件中选择的数据返回到条目小部件等。

The first round using traditional coding (8 lines):第一轮使用传统编码(8行):

entries = {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}

a_dic, b_dic = {}, {}

for field, value in entries.items():
    if field == 'ther':
        for k,v in value.items():
            b_dic[k] = v
        a_dic[field] = b_dic
    else:
        a_dic[field] = value
    
print(a_dic)
“ {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}”

Second round I tried to use dictionary comprehension but the loop still there (6 lines):第二轮我尝试使用字典理解,但循环仍然存在(6 行):

entries = {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}

for field, value in entries.items():
    if field == 'ther':
        b_dic = {k:v for k,v in value.items()}
        a_dic[field] = b_dic
    else:
        a_dic[field] = value
    
print(a_dic)
“ {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}”

Finally, with a one-line dictionary comprehension statement (1 line):最后,用一行字典理解语句(1行):

entries = {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}

a_dic = {field:{k:v for k,v in value.items()} if field == 'ther' 
        else value for field, value in entries.items()}
    
print(a_dic)
“ {'name': 'Material Name', 'maxt': 'Max Working Temperature', 'ther': {100: 1.1, 200: 1.2}}”

I use python 3.8.3我使用 python 3.8.3

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