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getElementsByName不会遍历整个数组

[英]getElementsByName won't loop through entire array

The following code executes on the press of a button. 按下按钮即可执行以下代码。 It works fine alerting one string of the getElementsByName array, but when introduced to a loop, it still only alerts the first string value, and nothing more: 它可以很好地警告getElementsByName数组的一个字符串,但是当引入循环时,它仍然仅警告第一个字符串值,仅此而已:

function checkvals() {

var input = document.getElementsByName('ModuleTitle', 'ModuleCode', 'BuildingName', 'Day');
var i = 0;

for (i = 0; i <= input.length; i++){
alert(input[i].value);
}
}

That's because getElementsByName only accepts one argument, so it's only fetching the first name. 那是因为getElementsByName只接受一个参数,所以它只获取第一个名字。

You can build a full collection like this... 你可以像这样构建一个完整的集合......

var names = ['ModuleTitle', 'ModuleCode', 'BuildingName', 'Day'];

var input = [];
for(var i = 0; i < names.length; i++) {
    var name_els = document.getElementsByName(names[i]);
    for(var j = 0; j < name_els.length; j++) {
        input.push(name_els[j]);
    }
}

Then loop over the input Array, (or just do your work in the inner loop) . 然后遍历input数组, (或者只是在内部循环中完成工作)


Additionally, you have a bug. 此外,您还有一个错误。

This... 这个...

for (i = 0; i <= input.length; i++){

should be this... 应该是这个...

for (i = 0; i < input.length; i++){

...otherwise, you'll go one past the last index. ...否则,你会超过最后一个索引。

That's because getElementsByName only takes a single name argument, and returns all elements with that value for their name attribute. 这是因为getElementsByName只需要一个 name的说法,并为他们的那个值返回的所有元素name属性。 (See https://developer.mozilla.org/en/DOM/document.getElementsByName .) If you have multiple name s to look up, you'll have to call it multiple times. (请参阅https://developer.mozilla.org/en/DOM/document.getElementsByName 。)如果要查找多个name ,则必须多次调用它。

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