[英]Printing a centered pyramid in Java with ascending and descending numbers
I'm trying to print a centered pyramid of 2^n, where 2^row# is the centered number of each row, the numbers to the left are ascending to 2^row# and the numbers to the right are descending. 我正在尝试打印2 ^ n的中心金字塔,其中2 ^ row#是每行的中心编号,左边的数字升至2 ^ row#,右边的数字降序。 I'm pretty new to Java and it took me a really long time to get this much.
我是Java的新手,我花了很长时间才得到这么多。 But now I'm stuck.
但是现在我被卡住了。 The last row is the only row that is correct.
最后一行是唯一正确的行。 I don't know how to make it so 64 is not printed on every line.
我不知道怎么做,所以不是每行都打印64。 Can anyone please give me a hint?
任何人都可以给我一个提示吗?
I've tried messing with every single parameter - starting the last loop with the first row, the last row, changing the starting power, etc. and I just can't figure it out. 我试过弄乱每个参数-从第一行,最后一行开始最后一个循环,更改启动功率等,但我只是想不通。
Thank you for any hints! 谢谢你的任何提示!
public static void main (String [] args){
int row;
for (row = 0; row <= 8; row++){ // Prints each row
for (int spaces = 8; spaces >= row; spaces --){ // Prints out spaces to left
System.out.print(" ");
}
int power1 = 0; // Power that 2 is being raised to
for (int i = 0; i < row; i++) { // Prints left side of the pyramid
System.out.print(" " + (int)Math.pow(2, power1));
power1++;
}
int power2 = 7;
for (int i = 1; i < row; i++) { // Prints right side of the pyramid
power2--;
System.out.print(" " + (int)Math.pow(2, power2));
}
System.out.println();
}
}
}
Your problem lies in the fact you always start the right side of the pyramid at 2^7, since you hard code the power2 = 7 decleration and assignment. 你的问题在于你总是以2 ^ 7开始金字塔的右侧,因为你硬编码power2 = 7 decleration和赋值。 If you start this value instead at the current row - 1, you get the behavior you're looking for.
如果您在当前行 - 1处启动此值,则会获得您正在寻找的行为。 Code:
码:
public static void main (String [] args){
int row;
for (row = 0; row <= 8; row++){ // Prints each row
for (int spaces = 8; spaces >= row; spaces --){ // Prints out spaces to left
System.out.print(" ");
}
int power1 = 0; // Power that 2 is being raised to
for (int i = 0; i < row; i++) { // Prints left side of the pyramid
System.out.print(" " + (int)Math.pow(2, power1));
power1++;
}
int power2 = row - 1;
for (int i = 1; i < row; i++) { // Prints right side of the pyramid
power2--;
System.out.print(" " + (int)Math.pow(2, power2));
}
System.out.println();
}
This part is not right. 这部分不对。
int power2 = 7;
for (int i = 1; i < row; i++) { // Prints right side of the pyramid
power2--;
System.out.print(" " + (int)Math.pow(2, power2));
}
On row 2 you get power2=6 so you display 2^6=64. 在第2行,您得到power2 = 6,因此显示2 ^ 6 = 64。
You should instead be doing something like 你应该做类似的事情
int power2 = power1;
for (int i = 1; i < row; i++) { // Prints right side of the pyramid
power2--;
System.out.print(" " + (int)Math.pow(2, power2));
}
You are assigning constant to power2 instead of depending value on row. 您正在为power2分配常量,而不是依赖于行的值。 Can you try this please.
你能试试吗?
int power2 = row-1; int power2 =第1行;
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