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将 time_t 转换为 int

[英]Converting time_t to int

I want to convert a given time into epoch(time_t) and vice versa.我想将给定的时间转换为纪元(time_t),反之亦然。 can anyone tell what is the routine or algorithm for this?谁能说出这的例程或算法是什么?

Thanks谢谢

Update更新

 epoch_strt.tm_sec = 0;
 epoch_strt.tm_min = 0;
 epoch_strt.tm_hour = 0;
epoch_strt.tm_mday = 1;
epoch_strt.tm_mon = 1;
epoch_strt.tm_year = 70;
 epoch_strt.tm_isdst = -1;

double nsecs = difftime(curtime, basetime);//current time from system, I converrting it to struct tm

but this always return 32399 for some reason.但这总是出于某种原因返回 32399 。

You should cast it to a long int instead of int .您应该将其转换为long int而不是int

long int t = static_cast<long int> (time(NULL));

An int might not be enough to hold the time, for example, on my platform, time_t is a typedef of __int64 . int可能不足以容纳时间,例如,在我的平台上, time_t__int64typedef

Whatever you're doing with time_t , you'll probably be best off using the <chrono> library.无论您使用time_t做什么,最好使用<chrono>库。 Then you can convert to and from time_t , if necessary.然后,您可以根据需要在time_t进行转换。 Hopefully you can just do what you need in <chrono>希望你可以在<chrono>做你需要的

#include <chrono>

int main() {
    auto a = std::chrono::system_clock::now()
    time_t b = std::chrono::system_clock::to_time_t(a);
    auto c = std::chrono::system_clock::from_time_t(b);
}

Update:更新:

The C++ standard library doesn't yet have an API for dates as good as <chrono> is for time. C++ 标准库还没有像<chrono>适用于时间的 API。 You can use the Boost date library or you can fall back on the C date library:您可以使用 Boost 日期库,也可以使用 C 日期库:

#include <ctime>
#include <chrono>
#include <iostream>

int main() {
    std::tm epoch_start = {};
    epoch_start.tm_sec = 0;
    epoch_start.tm_min = 0;
    epoch_start.tm_hour = 0;
    epoch_start.tm_mday = 1;
    epoch_start.tm_mon = 0;
    epoch_start.tm_year = 70;
    epoch_start.tm_wday = 4;
    epoch_start.tm_yday = 0;
    epoch_start.tm_isdst = -1;

    std::time_t base = std::mktime(&epoch_start);

    auto diff = std::chrono::system_clock::now() - std::chrono::system_clock::from_time_t(base);
    std::chrono::seconds s = std::chrono::duration_cast<std::chrono::seconds>(diff);

    std::cout << s.count() << '\n';
}

To convert a struct tm to a time_t , use mktime .要将struct tm转换为time_t ,请使用mktime To convert a time_t to a struct tm , use either gmtime or localtime .要将time_t转换为struct tm ,请使用gmtimelocaltime

Sample :样品

#include <iostream>
#include <ctime>

int main () {
    std::time_t now = std::time(0);

    std::tm *now_tm = gmtime(&now);

    std::tm tomorrow_tm(*now_tm);

    tomorrow_tm.tm_mday += 1;
    tomorrow_tm.tm_hour = 0;
    tomorrow_tm.tm_min = 0;
    tomorrow_tm.tm_sec = 0;

    std::time_t tomorrow = std::mktime(&tomorrow_tm);

    double delta = std::difftime(tomorrow, now);

    std::cout << "Tomorrow is " << delta << " seconds from now.\n";
}


UPDATE 2 更新 2

 #include <iostream> #include <ctime> #include <cassert> // Display the difference between now and 1970-01-01 00:00:00 // On my computer, this printed the value 1330421747 int main () { std::tm epoch_strt; epoch_strt.tm_sec = 0; epoch_strt.tm_min = 0; epoch_strt.tm_hour = 0; epoch_strt.tm_mday = 1; epoch_strt.tm_mon = 0; epoch_strt.tm_year = 70; epoch_strt.tm_isdst = -1; std::time_t basetime = std::mktime(&epoch_strt); std::time_t curtime = std::time(0); long long nsecs = std::difftime(curtime, basetime); std::cout << "Seconds since epoch: " << nsecs << "\\n"; assert(nsecs > 42ll * 365 * 24 * 60 * 60); }

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