十六进制字符串到int数组转换

Question

I am stuck with these problem that how to convert a hex string to unsigned byte array or an Integer array..

Please look in this example.

String s= "1f5621ff8963545a12152250"; //this is my hex string

i want to convert this string to an int array

int buff[]={0x1f,0x56,0x21,0xff,0x89,0x63,0x54,0x5a,0x12,0x15,0x22,0x50};

how could i do that...

thanks for help..

Answer 1

一个简单的方法：通过将String的长度除以2来计算int数组的长度。循环遍历字符串，调用substring()以创建双字符字符串“1f”，“56”等。传递每个字符串to Integer.parseInt(string, 16) （第二个参数表示参数是十六进制字符串。）在计算数据时将结果存储在数组中。

Answer 2

Iterate through the string and every two elements of the string create the integer like this:

0Xmm, where mm are the two elements you've just scanned.

Then you increase the index of your array and keep iterating through the string and adding to the current "top" place of the array.