Android Java分割为4个整数

Question

I receive an address in the form of "street number postcode city" (as a string). What I want to do is split the street and number from the postcode and city. Normally you can split on whitespace. But some streetnames have also whitespace in them, example: "Emile Van Ermengemlaan". So split on whitespace is no option.

The postcode is always 4 single numbers for example "1234","8560", ... And I think this is the option. Split on the postcode. But I don't know how to do this. Any help?

EDIT: Examples:

1. Example 1

   "Graaf Karel De Goedelaan 1 8500 Kortrijk" => "Graaf Karel de Goedelaan 1" next line "8500 Kortrijk"

2. Example 2

   "Reigerstraat 24 8930 Lauwe" => "Reigerstraat 24" next line "8930 Lauwe"

Answer 1

Thats something untested. I created it on the fly, there might be some mistakes but the general idea should fit.

String s = "Graaf Karel De Goedelaan 1 8500 Kortrijk";

Pattern p = Pattern.compile("{4}[0-9]");
Matcher m = p.matcher(s);
while(m.find){
    String postcode = m.group(1);
}

// splits around postcode
String[] split = s.split({4}[0-9]);

p = Patter.compile("\D"); //non-digit
m = p.matcher(split[0]);
while(m.find){
    String street = m.group(1);
}


p = Patter.compile("\d"); //digit
m = p.matcher(split[0]);
while(m.find){
    String streetnumber = m.group(1);
}

String city = split[1].substring(1);

Answer 2

String input = "Graaf Karel De Goedelaan 1 8500 Kortrijk";
String[] results = input.split("([0-9]{4})");
String road = results[0].trim();
String city = results[1].trim();
String postcode = "";
Pattern p = Pattern.compile("([0-9]{4})");
Matcher m = p.matcher(input);
while(m.find()) {
    postcode = m.group(1);
}
System.out.println(input);
System.out.println("Road: " + road);
System.out.println("Postcode: " + postcode);
System.out.println("City: " + city);

Gives:
Graaf Karel De Goedelaan 1 8500 Kortrijk
Road: Graaf Karel De Goedelaan 1
Postcode: 8500
City: Kortrijk

And:
Reigerstraat 24 8930 Lauwe
Road: Reigerstraat 24
Postcode: 8930
City: Lauwe

Answer 3

This is an example of code that works for me. It performs these operations:

1. It splits the string based on whitespace, and each element is stored on an array of strings;
2. It checks the size of each element of the array;
3. If the size is == 4 (the number of characters of the postal code), then it checks (with a pattern) if the current element is a number;

4. If the current element is a number, then this element and the next element (the city) is stored on an ArrayList .

    import java.util.regex.Matcher; import java.util.regex.Pattern; import java.util.*; public class split{ private List<String> newline = new ArrayList<String>(); public split(){ String myString = "Graaf Karel De Goedelaan 1 8500 Kortrijk"; String array[] = myString.split("\\\\s+"); for(int z = 0;z<arr.length;z++){ int sizestr = array[z].length(); if(sizestr==4){/* if the generic string has 4 characters */ String expression = "[0-9]*"; CharSequence inputStr = array[z]; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if(matcher.matches()){/* then if the string has 4 numbers, we have the postal code" */ newline.add(array[z]); /* now we add the postal code and the next element to an array list" */ newline.add(array[z+1]); } } } Iterator<String> itr = newline.iterator(); while (itr.hasNext()) { String element = itr.next(); System.out.println(element); /* prints "8500" and "Kortrijk" */ } } public static void main(String args[]){ split s = new split(); } } 

For further info about the check of the string, take a look to this page , and, for the ArrayList Iterator, see this .

I hope this can help to solve your problem.

Answer 4

尝试使用JGeocoder的地址解析器 。

Answer 5

尝试使用split命令解析模式“，”，则只需解析parseInt