[英]Serializing JSON in .NET
I have wrote a basic web service using .net which I intend to use in a mobile app. 我已经使用.net编写了一个基本的Web服务,打算在移动应用程序中使用它。 It currently outputs Json however the structure it not quite what I need.
目前,它输出的是Json,但结构并不完全符合我的需要。
The models I've created 我创建的模型
[DataContract]
class PoiList
{
[DataMember]
public List<Poi> Pois { get; set; }
}
[DataContract]
class Poi
{
[DataMember]
public string title { get; set; }
[DataMember]
public string latitude { get; set; }
[DataMember]
public string longitude { get; set; }
}
Then i added some test data: 然后我添加了一些测试数据:
PoiList poiList = new PoiList
{
Pois = new List<Poi>()
};
Poi p = new Poi
{
title = "whatever",
latitude = "-2.45554",
longitude = "52.5454645"
};
poiList.Pois.Add(p);
p = new Poi
{
title = "weeee",
latitude = "-2.45554",
longitude = "52.5454645"
};
poiList.Pois.Add(p);
string ans = JsonConvert.SerializeObject(poiList, Formatting.Indented);
This is what the returned string looks like: 返回的字符串如下所示:
{ "Pois": [ { "title": "shit", "latitude": "-2.45554", "longitude": "52.5454645" }, { "title": "weeee", "latitude": "-2.45554", "longitude": "52.5454645" } ] }
...and this is what I want the outputted Json to look like: ...这就是我想要输出的Json的样子:
string TempString = @"{ ""pois"":
[{ ""poi"":
{
""title"": ""Test title"",
""latitude"": ""-2.4857856"",
""longitude"": ""54.585656""
}},
{ ""poi"":
{
""title"": ""Halfords"",
""latitude"": ""-2.575656"",
""longitude"": ""53.5867856""
}}]}";
Basically the only difference being the "poi" next to each object in the list. 基本上,唯一的区别是列表中每个对象旁边的“ poi”。 Is there a simple way to include this?
有没有简单的方法可以包含此内容? I should add I am using the newtonsoft.json package.
我应该添加我正在使用newtonsoft.json包。
I would suggest you go with the JSON that's being generated, as your target JSON contains unnecessary objects, IMO. 我建议您使用正在生成的JSON,因为目标JSON包含不必要的对象IMO。
Your target JSON has an object with a single field "pois", which contains a list of objects, each with a single field "poi" that contains an object with the fields "title", "latitude", and "longitude". 您的目标JSON有一个带有单个字段“ pois”的对象,该对象包含一个对象列表,每个对象都有一个单个字段“ poi”,其中包含一个带有字段“ title”,“ latitude”和“ longitude”的对象。
To access a single title field, you would need to do the following: 要访问单个标题字段,您需要执行以下操作:
poisObj.pois[0].poi.title
If you go with the JSON that's generated by your object structure, you would access a single title field like so: 如果使用对象结构生成的JSON,则可以访问单个标题字段,如下所示:
poisObj.pois[0].title
That having been said, if you absolutely must target that JSON structure, you'll need another DataContract object, as follows: 话虽如此,如果您绝对必须以该JSON结构为目标,则需要另一个DataContract对象,如下所示:
[DataContract]
class PoiList
{
[DataMember]
public List<PoiPoi> Pois { get; set; }
}
[DataContract]
class PoiPoi
{
[DataMember]
public Poi poi { get; set; }
}
[DataContract]
class Poi
{
[DataMember]
public string title { get; set; }
[DataMember]
public string latitude { get; set; }
[DataMember]
public string longitude { get; set; }
}
Go with the default structure the only thing the "poi" gives you is what "type" the object is, which JSON doesn't really have a concept of. 使用默认结构,“ poi”唯一给您的就是对象的“类型”,而JSON并没有这个概念。 If you want to include type information, try :-
如果要包括类型信息,请尝试:-
var jsonSerializerSettings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.Objects,
TypeNameAssemblyFormat = FormatterAssemblyStyle.Full,
};
var json = JsonConvert.SerializeObject(o, Formatting.None, jsonSerializerSettings);
this will give you a field _type_
which is useful especially if you have a list of various types of objects. 这将为您提供一个
_type_
字段,该字段特别有用,如果您具有各种类型的对象的列表。 Json.Net then knows how to recreate the objects using this _type_
field. 然后,Json.Net知道如何使用此
_type_
字段重新创建对象。
No need to declare many tiny classes just to output a json string. 无需声明许多小类即可输出json字符串。 You can create an anonymous object to serialize like below:
您可以创建一个匿名对象以进行序列化,如下所示:
var obj = new { pois = new List<object>() };
obj.pois.Add(new { poi = new {title = "Test title", latitude = "-2.4857856", longitude = "54.585656" } });
obj.pois.Add(new { poi = new {title = "Halfords" , latitude = "-2.4857856", longitude = "53.5867856" } });
string json = JsonConvert.SerializeObject(obj, Newtonsoft.Json.Formatting.Indented);
Console.WriteLine(json);
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