使用分类器创建一个WAR和一个包含该WAR作为一个模块的EAR？

Question

I understand that this might sound like the wrong thing to do, but what I'm attempting is to have a Maven POM (module) that when installed will package as WAR but in addition, as an EAR that contains the single WAR.

To clarify: I am looking to wrap each existing WAR in my project in its own EAR.

The reason behind my desire is because I am looking at restructuring the way we package our released WARs so that each is contained within an EAR (but also still generate an independent WAR artifact for development ease). I am not keen to create a new module that depends on the WAR and package it in an EAR because I have loads of WARs.

Currently I am trying this, for one of my existing WAR modules, without success using a classifier :

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
    <parent>
        ...
    </parent>
    <modelVersion>4.0.0</modelVersion>
    <artifactId>se-index-webapp</artifactId>
    <packaging>war</packaging>

    <build>
        <plugins>

            <plugin>
                <artifactId>maven-war-plugin</artifactId>
                <configuration>
                    ...
                </configuration>
            </plugin>

            <plugin>
                <artifactId>maven-ear-plugin</artifactId>
                <version>2.7</version>
                <configuration>
                    <finalName>search-index.ear</finalName>
                    <classifier>ear</classifier>
                    <unpackTypes>war</unpackTypes>
                    <modules>
                        <webModule>
                            <groupId>${project.groupId}</groupId>
                            <artifactId>${artifactId}</artifactId>
                            <uri>search-index.war</uri>
                            <bundleFileName>search-index.war</bundleFileName>
                            <contextRoot>/SearchIndex</contextRoot>
                        </webModule>
                    </modules>
                </configuration>
                <dependencies>
                    <dependency>
                        <groupId>${project.groupId}</groupId>
                        <artifactId>${artifactId}</artifactId>
                        <version>${project.version}</version>
                        <type>war</type>
                    </dependency>
                </dependencies>
            </plugin>

        </plugins>
    </build>

    <dependencies>  
        ...
    </dependencies>

</project>

I get the error:

Artifact[war:myproject:se-index-webapp] is not a dependency of the project

Is what I'm trying to do possible?

Answer 1

The first thing you have to change is based on Maven conventions to have a separate EAR module which results in the following structure:

  +-- root (pom.xml)
       +--- mod-ear (pom.xml) packaging: ear
       +--- mod-war (pom.xml) packaging: war

Than you can define the dependencies to your mod-war module very simple by giving

   <dependencies>
      <dependency>
          <groupId>..</groupId>
          <artifactId>..</artifactId>
          <version>..</version>
      </dependency>
   ...
  </dependencies> 

The advantage of this approach that you have separated the information which belong to ear and them which belong to ear module.

The result is you can do a mvn clean package on the root level or do a mvn install / deploy which deploys war as well as ear into your repository.