如何在服务器端获取HTTPS发布请求的内容？

Question

I have a C client which use libcurl to send xml packet to Apache server via HTTPS.

some parts of the client code as:

curl_easy_init();
curl_easy_setopt(curl, CURLOPT_URL, "https://example.com/test.php");
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, send_buf);
curl_easy_setopt(curl, CURLOPT_POSTFIELDSIZE, strlen(send_buf));
curl_easy_setopt(curl, CURLOPT_POST, 1L);
res = curl_easy_perform(curl);

The content of send_buf is sent to https apache server ( https://example.com/test.php ), but on the Apache server side, how can I use test.php to get the content of send_buf? Any other scripts are welcome. thanks

Any example codes?

Answer 1

I may be a little unclear on your question, but I'm assuming send_buf is in the standard format, ie,

foo=bar&baz=boo&x=17+cats+etc

In that case, in your receiving PHP script (test.php) the $_POST variable will be initialized as follows:

$_POST['foo'] = "bar"
$_POST['baz'] = "boo"
$_POST['x'] = "17 cats etc"

So you can access a value by using $_POST['foo'].

Hope that helps.

Answer 2

To get everything that is sent (POST) to your Apache server via your test.php file, you can use:

<?php
    var_dump($_POST);
?>

You could also use $_GET if you wanted to get everything passed in the URL (like: https://example.com/test.php?myvar=value ). Finally, $_REQUEST contains both $_POST and $_GET.

If you post a variable called myvar via your C code, you can retrieve the value in your test.php file with:

<?php
    print $_POST['myvar'];
?>