如何删除此二维指针数组？ 制作一个析构函数

Question

malla = new Celula**[n + 2];  
for(int i = 0 ; i < n + 2 ; ++i){  
     malla[i] = new Celula*[m + 2];
     for(int j = 0 ; j < m + 2 ; ++j){
         malla[i][j] = new Celula[m];
     }
}

I'm making this code and I allocate memory like this (I want a n*m array of pointers to Celula, is okay? Now I need a destructor.

Now I don't know how to access to an object in this array and:

malla[i][j].setestado(true);

doesn't work.

Answer 1

Don't use pointers .

std::vector<std::vector<Celula> > malla(n, std::vector<Celula>(m));

// …
malla[1][2].setestado(true);

Upshot: one line instead of seven, easier usage, no delete needed anywhere.

As an aside, it's conventional to use English identifiers in code. If nothing else, this has the advantage that people can help you better if they don't speak the same language as you.

Answer 2

Seriously consider the advice of @konrad's . If anyhow you want to go with raw array's , you can do :

To deallocate :

 for(int i = 0 ; i < n + 2 ; ++i)
 {
 for(int j = 0 ; j < m + 2 ; ++j) delete[] malla[i][j] ;
 delete[] malla[i];
 }
 delete[] malla;

To access the object :

 malla[i][j][_m].setestado(true);

Edit :

if malla[i][j] is pointer to simply object then destructor/deallocation will look like :

 for(int i = 0 ; i < n + 2 ; ++i)
 {
 for(int j = 0 ; j < m + 2 ; ++j) delete malla[i][j] ;
 delete[] malla[i];
 }
 delete[] malla;

Access object/member can be done like : (*malla[i][j]).setestado(true); or malla[i][j]->setestado(true);