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在渐变上获取特定位置的颜色

[英]Get color in specific location on gradient

I have the following GradientStopCollection : 我有以下GradientStopCollection

GradientStopCollection grsc = new GradientStopCollection(3);
grsc.Add(new GradientStop(Colors.Red, 0));
grsc.Add(new GradientStop(Colors.Yellow, .5));
grsc.Add(new GradientStop(Colors.Green, 1));

Can I get the color at a specific "location"? 我可以在特定的“位置”获得颜色吗? For example: 例如:

  • Location 0: Red 位置0:红色
  • Location .5: Yellow 位置.5:黄色
  • Location .75: Yellow<~>Green 位置.75: Yellow<~>Green

Is there an API in WPF / some third party library that could do that? WPF /某些第三方库中是否有API可以做到这一点?

To get a color at a specific point is necessary to understand the gradient in question, and this is not the role of class GradientStopCollection. 要获得特定点的颜色,有必要了解有问题的渐变,这不是GradientStopCollection类的作用。 The concept of this class is not to understand a gradient, but should be a simple collection of support to a gradient. 这个类的概念不是要理解渐变,而应该是对渐变的简单支持集合。

Is important that you understand the concept of each class. 重要的是要了解每个班级的概念。

To get a color, you need to instantiate a class that represents a gradient using the gradient to paint and finally get their color from the painting. 要获得颜色,您需要使用渐变来实例化一个表示渐变的类,并最终从绘画中获取颜色。

but I'll give you a quicker solution. 但我会给你一个更快的解决方案。 You can use a gradient algorithm to generate a single point. 您可以使用渐变算法生成单个点。 This is an implementation of how to do this using a linear gradient algorithm: 这是使用线性渐变算法如何执行此操作的实现:

public static class GradientStopCollectionExtensions
{
    public static Color GetRelativeColor(this GradientStopCollection gsc, double offset)
    {
        var point = gsc.SingleOrDefault(f => f.Offset == offset);
        if (point != null) return point.Color;

        GradientStop before = gsc.Where(w => w.Offset == gsc.Min(m => m.Offset)).First();
        GradientStop after = gsc.Where(w => w.Offset == gsc.Max(m => m.Offset)).First();

        foreach (var gs in gsc)
        {
            if (gs.Offset < offset && gs.Offset > before.Offset)
            {
                before = gs;
            }
            if (gs.Offset > offset && gs.Offset < after.Offset)
            {
                after = gs;
            }
        }

        var color = new Color();

        color.ScA = (float)((offset - before.Offset) * (after.Color.ScA - before.Color.ScA) / (after.Offset - before.Offset) + before.Color.ScA);
        color.ScR = (float)((offset - before.Offset) * (after.Color.ScR - before.Color.ScR) / (after.Offset - before.Offset) + before.Color.ScR);
        color.ScG = (float)((offset - before.Offset) * (after.Color.ScG - before.Color.ScG) / (after.Offset - before.Offset) + before.Color.ScG);
        color.ScB = (float)((offset - before.Offset) * (after.Color.ScB - before.Color.ScB) / (after.Offset - before.Offset) + before.Color.ScB);

        return color;
    }
}

PS: This algorithm assumes there are no stops with the same offset. PS:该算法假设没有具有相同偏移的停止。 If there are multiple stops with the same offset a InvalidOperationException will be thrown. 如果有多个具有相同偏移量的停靠点,则将抛出InvalidOperationException

Add this class in your current context (namespace context) 在当前上下文中添加此类(名称空间上下文)

To get your color in any place you insert something like this: 要在任何地方获取颜色,请插入以下内容:

var color = grsc.GetRelativeColor(.75);

I've tried the method written by Jonny Piazzi. 我尝试过Jonny Piazzi写的方法。 But it didn't work correctly. 但它无法正常工作。
So I write my own one below: 所以我在下面写下自己的一个:

private static Color GetColorByOffset(GradientStopCollection collection, double offset)
{
    GradientStop[] stops = collection.OrderBy(x => x.Offset).ToArray();
    if (offset <= 0) return stops[0].Color;
    if (offset >= 1) return stops[stops.Length - 1].Color;
    GradientStop left = stops[0], right = null;
    foreach (GradientStop stop in stops)
    {
        if (stop.Offset >= offset)
        {
            right = stop;
            break;
        }
        left = stop;
    }
    Debug.Assert(right != null);
    offset = Math.Round((offset - left.Offset)/(right.Offset - left.Offset), 2);
    byte a = (byte) ((right.Color.A - left.Color.A)*offset + left.Color.A);
    byte r = (byte) ((right.Color.R - left.Color.R)*offset + left.Color.R);
    byte g = (byte) ((right.Color.G - left.Color.G)*offset + left.Color.G);
    byte b = (byte) ((right.Color.B - left.Color.B)*offset + left.Color.B);
    return Color.FromArgb(a, r, g, b);
}

I hope it works for you! 我希望这个对你有用!

I've used this method in my xaml code below to show a specified number as heat map position. 我在下面的xaml代码中使用了这个方法,将指定的数字显示为热图位置。

<LinearGradientBrush x:Key="CountBrush" StartPoint="0 0" EndPoint="1 0">
    <GradientStop Offset="0.00" Color="ForestGreen"/>
    <GradientStop Offset="0.50" Color="Yellow"/>
    <GradientStop Offset="1.00" Color="OrangeRed"/>
</LinearGradientBrush>
<local:Int32ToColorConverter x:Key="CountToColorConverter" Min="0" Max="200" LinearBrush="{StaticResource CountBrush}"/>
  foreach (var gs in gsc)
            {
                if (gs.Offset == offset) return gs.Color; //new line added
                if (gs.Offset < offset && gs.Offset > before.Offset)
                {
                    before = gs;
                }

                if (gs.Offset > offset && gs.Offset < after.Offset)
                {
                    after = gs;
                }
            }

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