从字符串中提取特定文本

Question

This is the string: "-random text- $0.15 USD"

What I want to extract is the "0.15" behind, excluding the $ and USD. So the text will only contain "0.15" with all other words gone.

How do I go about doing this?

Thanks in advance :)

Answer 1

Using regexes

string str = "-random text- $0.15 USD";

Regex rx = new Regex(@"(?<=\$)[0-9]+\.[0-9]+(?= USD$)");
var res = rx.Match(str);

if (res.Success) {
    var res2 = res.ToString();
}

The "main" part is [0-9]+\\.[0-9]+ (one or more digits followed by a . followed by one or more digits). This expression must follow a $ sign (?<=\\$) and must be followed by USD (there is a space before USD ) plus end of string (?= USD$) .

Online test: http://regexr.com?30aot

Answer 2

var result = Regex.Match("-random text- $0.15 USD",   @"\$([ \d\.]+)USD")
                  .Groups[1].Value;

Answer 3

Use a regex. Something like:

\d+\.*\d+

Answer 4

Regular expressions are your friend here.

Use the RegEx class ( System.Text.RegularExpressions ), using a pattern of ([\\d\\.]+) to extract the number + decimal place.

Answer 5

you can do something like this

    string str = "-random text- $0.15 USD";
    int startIndex = str.IndexOf("$")+1;
    int length = str.IndexOf("USD", startIndex) - startIndex;
    string output = str.Substring(startIndex, length).Trim();

Answer 6

Why use regexes when you can use the built-in String methods?

 int startIndex = myRandomString.LastIndexOf("$") + 1;
 int lastIndex = myRandomString.LastIndexOf("U") - startIndex;

 string price = random.Substring(startIndex, lastIndex);

Answer 7

Try this:

string sentence = "-random text- $0.15 USD";
string[] doubleArray = System.Text.RegularExpressions.Regex.Split(sentence, @"[^0-9\.]+")
                       .Where(c => c != "." && c.Trim() != "").ToArray();
if (doubleArray.Count() > 0)
{
     double value = double.Parse(doubleArray[0]);
}

output:
.15

Answer 8

你有没有想过使用正则表达式 ？

Regex.Match("0.15");