[英]Correcting division by zero in SQLite
In my SQLite statement below there is a problem with division by zero in the case count(t2.ref_id)
is zero. 在下面的SQLite语句中,在
count(t2.ref_id)
为零的情况下存在除零的问题。
Could I adjust the SQLite statement so that if the count(t2.ref_id)
is zero the scarsity (scarsity factor) will be higher than the highest non-zero scarsity? 我可以调整SQLite语句,以便如果
count(t2.ref_id)
为零,则稀疏性(稀释因子)将高于最高的非零稀释度吗?
select t1.id, cast(:totalItems as float) / count(t2.ref_id) as scarsity
from t1 left join t2 on t1.id = t2.ref_id
group by t1.id
order by scarsity
You need to check for the value 0 and do something different. 您需要检查值0并执行不同的操作。 One common way is to divide by
NULL
as many SQL varieties have NULLIF()
to turn a value into a NULL
instead. 一种常见的方法是除以
NULL
因为许多SQL变量具有NULLIF()
以将值转换为NULL
。
select t1.id, cast(:totalItems as float) / NULLIF(count(t2.ref_id), 0) as scarsity
from t1 left join t2 on t1.id = t2.ref_id
group by t1.id
order by scarsity
But I'm not sure that SQLite has NULLIF()
, so you could use the more long winded CASE
version instead... 但是我不确定SQLite是否有
NULLIF()
,所以你可以使用更长的winded CASE
版本......
select t1.id, cast(:totalItems as float) / CASE WHEN count(t2.ref_id) = 0 THEN NULL ELSE count(t2.ref_id) END as scarsity
from t1 left join t2 on t1.id = t2.ref_id
group by t1.id
order by scarsity
The COUNT()
won't be calculated twice even though you typed it twice. 即使您键入两次,
COUNT()
也不会被计算两次。 The value will be re-used :) 该值将被重用:)
Alternatively, do something completely different if you get 0 rows... 或者,如果你获得0行,做一些完全不同的事情......
select t1.id, CASE WHEN count(t2.ref_id) = 0 THEN 9999999 ELSE cast(:totalItems as float) / count(t2.ref_id) END as scarsity
from t1 left join t2 on t1.id = t2.ref_id
group by t1.id
order by scarsity
Then you can check for NULLs as being the highest value, or just check for 9999999, etc, etc. 然后你可以检查NULL是最高值,还是只检查9999999等等。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.