[英]PHP or statement ||
Use of ||
使用
||
(or) (要么)
I got so many values which I need to compare with same variable, is there a better way to write more efficiently such as $city == -35 || -34 || -33
我有这么多的值,我需要与同一个变量进行比较,是否有更好的方法来更有效地编写,例如
$city == -35 || -34 || -33
$city == -35 || -34 || -33
$city == -35 || -34 || -33
or even simpler so that I don't have to repeat variable name since it's the same variable only value keep changing. $city == -35 || -34 || -33
甚至更简单,这样我就不必重复变量名,因为它是相同的变量,只有值不断变化。
<?php
if ($city == -35 || $city == -34 || $xcity == -33)
{
$region = "noindex";
}
?>
Any suggestions? 有什么建议么?
You might use in_array()
你可以使用
in_array()
if (in_array($city, array(-35, -34, -33))) {
$region = "noindex";
}
Or if they are consecutive ( I suspec they aren't and this is just an example) 或者如果它们是连续的(我怀疑它们不是,这只是一个例子)
in_array($city, range(-35, -33))
你可以使用:
if (in_array($city, array(-35, -34, -33))
Assuming that $xcity
is a typo, 假设
$xcity
是拼写错误,
switch ($city)
{
case -35:
case -34:
case -33:
$region = "noindex";
break;
}
Use associative array. 使用关联数组。 in_array compare each element in array with your var.
in_array将数组中的每个元素与var进行比较。 Associative array used hashtable.
关联数组使用哈希表。 It faster.
它更快。
$cities = array(-33 => 1, -34 => 1, -35 => 1);
if (isset($cities[$city])) {
$region = "noindex";
}
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