查找随机生成的10个数字数组的模式

Question

I'm attempting to make this program

public class Statistics {

    public static void main(String[] args) {
        final int SIZE = 10;
        int sum =0;

        int[] numArray= new int [SIZE];

        for (int c=0; c < SIZE; c++)
        {
            numArray[c]=(int)(Math.random()*6+1);
            System.out.print( numArray[c]+   " ");

            sum+=numArray[c];
        }

        System.out.println("\nSum of all numbers is " + sum);
        System.out.println("\n Mean of numbers is " + (sum) / 5);
    }
}

Calculate the mode of the randomly generated array.

I've seen source codes posted where they use a seperate method called computemode, but I don't kno where to place this second method within my code. I'm sorry, I am very very green when it comes to programming. I'm being taught Java as my first language and so far its overwhelming.

If someone could post the syntax with detailed instruction/explanation I'd be so grateful.

Answer 1

The mode is quite easy to compute. One way, assuming your inputs are bounded, is to simply have an array that tracks the number of occurrences of each number:

int[] data; //your data bounded by 0 and MAX_VALUE
int[] occurrences = new int[MAX_VALUE+1];

for ( int datum : data ) {
    occurrences[newNumber]++;
}

Then figure out the index(es) in occurrences that has the highest value.

int maxOccurrences = Integer.MIN_VALUE;
int mode = -1;

for ( int i = 0; i < occurrences.length; i++ ) {
    if ( occurrences[i] > maxOccurrences ) {
        maxOccurrences = occurrences[i];
        mode = i;
    }
}

You would have to adjust this to handle multiple modes.