在php中创建一个函数来检查获取值的顺序是dd / mm / yyy

Question

I'm currently building a room booking system and was wondering how to check if the user has entered a date (get value) in the correct UK format of dd/mm/yyyy.

$uk_date = $_GET["date"];

For example to avoid a situation where the user types in 12/2012 or 2012 or uses the incorrect separators.

Thanks in advance!

Answer 1

The best would be DateTime::createFromFormat :

$date = DateTime::createFromFormat('d/m/Y', $uk_date);
$errors = DateTime::getLastErrors();
if($errors['warning_count'] || $errors['error_count']) {
    // something went wrong, you can look into $errors to see what exactly
}

If the parsing is successful then you have in your hands a DateTime object that provides lots of useful functions. One of the most important is DateTime::format which will let you get data out of the object, eg:

$year = $date->format('Y');

Answer 2

Use a regex code like this:

$str = '12/12/2012';
$regex = '#^\d{1,2}([/-])\d{1,2}\1\d{4}$#';
if (preg_match($regex, $str, $m))
   echo "valid date\n";

Answer 3

Try this function:

public static function CheckValidDate($sDate) {
    $sDate = str_replace('/', '-', $sDate);
    preg_match('/^(\d{2})-(\d{2})-(\d{4})$/', $sDate, $xadBits);
    if ($xadBits)
      return checkdate($xadBits[2], $xadBits[1], $xadBits[3]);
    else
      return false;
}

Visit the reference: http://php.net/manual/en/function.checkdate.php

Thanks for the comment @SalmanA

Answer 4

Try this regular expression:

$pattern = '|^[\d]{,2}/[\d]{,2}/[\d]{,4}$|is';
if (preg_match($pattern, $date, $match)) {
  echo 'ok!';
}