有没有办法比较两个void指针在C中断言相同的类型？

Question

I am learning C and attempting a crude implementation of a linked list in C. Long story short I have a struct containing only a void pointer(element) and another pointer to the next node.(code to follow) My question is, when passing the head node and some other node into a new function, is there any way to ensure the two elements are of the same type? The two nodes should be able to hold any kind of data. Ive tried comparing with sizeof(), but am unable to deference a void pointer. Thanks in advance!

struct Node{
    void* element;
    struct Node* next;
}

This is the code for the nodes, I just need a way to compare them with assert to ensure a linked list with all of the same element types! Thanks!

Answer 1

不 - 你通常想要避免像这样的设计，但是如果你真的无法避免它，你通常需要在节点中放置一个枚举来告诉你它包含的数据类型。

Answer 2

A void* is precisely a type-less pointer. In other words, all that your program knows is that it's a pointer to SOMETHING. This is useful, but it specifically (intentionally) isn't what you're looking for.