有没有一种方法可以使用uniq仅比较前n个字符？

Question

According to the documentation, 根据文档，

The command can be used to ignore the first n characters 该命令可用于忽略前n个字符

Suppose I wish to have the following 假设我希望有以下内容

03/08/2002,2,HUST,RICC,53.0,,2.3,J S BULLARD,,2,2,3/3,46.0,,,
03/08/2002,2,HUST,RICC,53.0,,WON,M J WALKER,,10,1,2/2,49.5,,,

Matched as identical based on the first 20 characters. 根据前20个字符进行匹配。 Is there a way to do this? 有没有办法做到这一点？

Answer 1

My uniq manual (coreutils 8.5) says: 我的uniq手册（coreutils 8.5）说：

 -w, --check-chars=N compare no more than N characters in lines

This however isn't standard (thus won't work on other Unixes). 但是，这不是标准的（因此在其他Unix上将无法使用）。