[英]Why am I getting this error, left of 'method' must have class/struct/union?
I am building three classes, Maze, MazeRow, and MazePoints, to hold a maze structures and I am having trouble with setting up my vector for the MazeRows.The below code is from my Maze class code. 我正在构建三个类,Maze,MazeRow和MazePoints,以保持迷宫结构,我在为MazeRows设置矢量时遇到问题。下面的代码来自我的Maze类代码。 I have included my header file for MazeRow.
我已将我的头文件包含在MazeRow中。 I am getting 3 errors each where i am calling a vector method.
我正在调用一个向量方法,每次得到3个错误。 Also myMazeRows is a private member variable of Maze Class
myMazeRows也是Maze Class的私有成员变量
//Maze Header File
#include "MazeRow.h"
#include <vector>
using namespace std;
namespace MazeSolver
{
class Maze
{
public:
Maze(int rows, int columns);
MazeRow * getRow(int row);
private:
vector<MazeRow> myMazeRows();
//Maze Implementation File
#include "stdafx.h"
#include "Maze.h"
#include <vector>
using namespace std;
using namespace MazeSolver;
Maze::Maze(int rows, int columns)
{
//Recieving the Compile Error (C2228)
myMazeRows.resize(rows);
//Initializing Each Row
for(int i=0; i< rows;i++) //Recieving the Compile Error ( C2228 )
myMazeRows.push_back(MazeRow(i,columns));
}
MazeRow* Maze::getRow(int row)
{
//Recieving the Compile Error (C2228)
return &myMazeRows.at(row);
}
//Maze Row Header File
class MazeRow
{
public:
MazeRow(int rowNum, vector<MazePoint>);
MazeRow(int rowNum, int mazPoints);
At least one error the Maze::GetRow() should be: Maze :: GetRow()应该至少有一个错误:
MazeRow* Maze::getRow(int row)
{
return &myMazeRows.at(row); // note the change from * to &
}
Another possibly is that your loop in Maze constructor is to i<rows-1
-- most likely should be i<rows
. 另一个可能是你的Maze构造函数中的循环是
i<rows-1
- 很可能应该是i<rows
。 This will not cause compilation error, but runtime problems. 这不会导致编译错误,但会导致运行时问题。
As Attila said, an error can be seen at this function: 正如Attila所说,在这个功能上可以看到一个错误:
MazeRow *Maze::getRow(int row)
{
return *myMazeRows.at(row);
}
If myMazeRows
were containing a MazeRow **
, then this would be valid, but You probably meant to take the address of the MazeRow
object, like so: 如果
myMazeRows
包含MazeRow **
,那么这将是有效的,但你可能想要获取MazeRow
对象的地址,如下所示:
MazeRow *Maze::getRow(int row)
{
// Ampersand (&) take the address of the row
return &myMazeRows.at(row);
}
For the std::vector
errors, make sure you either have using namespace std;
对于
std::vector
错误,请确保using namespace std;
at the top of your header file, or are using std::vector
, and ensure you have #include <vector>
as well. 在头文件的顶部,或者正在使用
std::vector
,并确保你也有#include <vector>
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.