如何使用XPath查询更新Jackrabbit中的XML内容？

Question

I am using Jackrabbit 2.4.0 and I am having trouble updating XML which has been imported using: 我正在使用Jackrabbit 2.4.0，但无法更新已使用以下方式导入的XML：

session.importXML(node.getPath(), is, ImportUUIDBehavior.IMPORT_UUID_CREATE_NEW);
session.save();

I have the following code that does the XML updating: 我有以下代码可以进行XML更新：

public void updateXML(InputStream is, String nodePath)
        throws RepositoryException, IOException, NamingException
{
    Session session = getSession();

    try
    {
        logger.debug("Updating path '" +nodePath +"'...");

        session.importXML(nodePath, is, ImportUUIDBehavior.IMPORT_UUID_COLLISION_REPLACE_EXISTING);
        session.save();
    }
    finally
    {
        if (session != null)
            session.logout();
    }
}

Assuming I have a the following imported to Jackrabbit under /notes : 假设我在/notes下将以下内容导入到Jackrabbit中：

<?xml version="1.0"?>
<note xmlns="http://testuri.org/note"
      xsi:schemaLocation="http://testuri.org/note file:///path/to/note.xsd"
      xmlns:nt="http://www.jcp.org/jcr/nt/1.0"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

    <id>123</id>
    <to>Me</to>
    <from>You</from>
    <heading>Meeting at five</heading>
    <body>With this you are hereby invited to the important meeting at five.</body>

</note>

Why does the following code to update the XML not work: 为什么以下代码无法更新XML：

    InputStream is = getClass().getClassLoader().getResourceAsStream("note-update.xml");

    serviceXML.updateXML(is, "//notes");

and I get the following error: 我收到以下错误：

    org.apache.jackrabbit.spi.commons.conversion.MalformedPathException: '//notes' is not a valid path. double slash '//' not allowed.

I do however have the following imported: 但是，我确实导入了以下内容：

/
/jcr:primaryType = rep:root
/jcr:system
/notes
/notes/jcr:primaryType = nt:unstructured
/notes/note:note
/notes/note:note/xsi:schemaLocation = http://testuri.org/note file:///path/to/note.xsd
/notes/note:note/jcr:primaryType = nt:unstructured
/notes/note:note/note:id
/notes/note:note/note:id/jcr:primaryType = nt:unstructured
/notes/note:note/note:id/jcr:xmltext
/notes/note:note/note:id/jcr:xmltext/jcr:xmlcharacters = 123
/notes/note:note/note:id/jcr:xmltext/jcr:primaryType = nt:unstructured
/notes/note:note/note:to
/notes/note:note/note:to/jcr:primaryType = nt:unstructured
/notes/note:note/note:to/jcr:xmltext
/notes/note:note/note:to/jcr:xmltext/jcr:xmlcharacters = Me
/notes/note:note/note:to/jcr:xmltext/jcr:primaryType = nt:unstructured
/notes/note:note/note:from
/notes/note:note/note:from/jcr:primaryType = nt:unstructured
/notes/note:note/note:from/jcr:xmltext
/notes/note:note/note:from/jcr:xmltext/jcr:xmlcharacters = You
/notes/note:note/note:from/jcr:xmltext/jcr:primaryType = nt:unstructured
/notes/note:note/note:heading
/notes/note:note/note:heading/jcr:primaryType = nt:unstructured
/notes/note:note/note:heading/jcr:xmltext
/notes/note:note/note:heading/jcr:xmltext/jcr:xmlcharacters = Meeting at five
/notes/note:note/note:heading/jcr:xmltext/jcr:primaryType = nt:unstructured
/notes/note:note/note:body
/notes/note:note/note:body/jcr:primaryType = nt:unstructured
/notes/note:note/note:body/jcr:xmltext
/notes/note:note/note:body/jcr:xmltext/jcr:xmlcharacters = With this you are hereby invited to the important meeting at five.
/notes/note:note/note:body/jcr:xmltext/jcr:primaryType = nt:unstructured

I have one single entry. 我只有一个条目。

Let's say I would like to update the note with id 123, how would I go about doing that using XPath? 假设我想更新ID为123的注释，我将如何使用XPath进行更新？

Thanks in advance for your help! 在此先感谢您的帮助！

Answer 1

Session.importXml takes a String path as its first argument. Session.importXml将字符串path作为其第一个参数。 As such, you should specify the location where to import the nodes. 这样，您应该指定导入节点的位置。

In your case, I believe that is /notes . 就您而言，我相信是/notes 。

如何使用XPath查询更新Jackrabbit中的XML内容？

问题描述

1 个解决方案

解决方案1
1 已采纳 2012-03-26 16:07:29

如何使用XPath查询更新Jackrabbit中的XML内容？

问题描述

1 个解决方案

解决方案1 1 已采纳 2012-03-26 16:07:29

解决方案1
1 已采纳 2012-03-26 16:07:29