[英]Initializer-string for char array is too long
I have read char four[4] = "four"; 我读过char char [4] =“ four”; What are the correct semantics for this statement? 该语句的正确语义是什么?
I am using Xcode
and writing Objective C
code. 我正在使用Xcode
并编写Objective C
代码。 I don't understand why: 我不明白为什么:
char words[4] = { "aardvark", "abacus", "allude", "zygote" };
gives a warning 发出警告
warning: Semantic Issue: Initializer-string for char array is too long 警告:语义问题:char数组的初始化字符串太长
but 但
char *words[4] = { "aardvark", "abacus", "allude", "zygote" };
works fine. 工作正常。 Kindly guide me. 请指导我。
I was not aware of the differences between an integer pointer and a character pointer. 我不知道整数指针和字符指针之间的区别。 Hence, I was confused. 因此,我感到困惑。 This helped me: http://www.computing.net/answers/programming/why-this-works-char-pointer-in-c/4444.html 这对我有帮助: http : //www.computing.net/answers/programming/why-this-works-char-pointer-in-c/4444.html
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