[英]MYSQL add row and count from diffrent table
I have mysql database with two tables. 我有两个表的mysql数据库。
First (information) 第一(信息)
+---------+------+----------+
| species | sex | user |
+---------+------+----------+
| bird | NULL | 1 |
| bird | f | 1 |
| cat | f | 1 |
| cat | m | 1 |
| dog | f | 1 |
| dog | m | 2 |
| hamster | f | 2 |
| snake | m | 1 |
+---------+------+----------+
Second (users) 第二(用户)
+--------+-----+
| user | id |
+--------+-----+
| amy | 1 |
| dav | 2 |
| mot | 3 |
| mmm | 4 |
| aaw | 5 |
| dsa | 6 |
+--------+-----+
I want to count and show values from table "information" for each user row on table "users" Like this 我想为表“ users”上的每个用户行计数并显示表“ information”中的值
+---------+------+----------+
| user | id | count |
+---------+------+----------+
| amy | 1 | 6 |
| dav | 2 | 2 |
| mot | 3 | 0 |
| mmm | 4 | 0 |
| aaw | 5 | 0 |
| dsa | 6 | 0 |
+---------+------+----------+
How can I do this query? 我该如何查询?
select users.user, users.id, count (species.name)
from users left join species
on users.id = species.user
group by users.user, users.id
order by count (species.name) desc
Isn't it something like: 是不是这样:
select u.user, u.id, count(i.user)
from user u
inner join information i on i.user = u.id
group by u.user, u.id
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