如何在RabbitMQ上进行非阻塞？

Question

I am new to RabbitMQ. I just started yesterday. I did few spikes on sending and consuming stuff. What I noticed was on their documentation and even on articles that I've read most of them are implementing the subscription piece in a way that they are looping it to get the message from a queue. How can I make it so that it will be event driven? What I wanted to accomplish is when a message is sent to a queue it will raise and event to the receiver and do something about it. Perhaps like displaying the message.

Your reply is greatly appreciated.

Best regards,

Answer 1

Should use EventingBasicConsumer. I have an example on my website that shows how it's used RabbitMQ Events using EventingBasicConsumer

Basically it's just a new consumer that exposes a Received event so you don't need to block.

Answer 2

Some of the examples use that looping style because it's easier to explain and understand.

You want to use IModel.BasicConsume instead of BasicGet . See the API Guide for examples (search for subscribe and consume).