javascript 至少一个数字和一个大写字母的正则表达式

Question

what would be the regular expression to check if a given string contains atleast one number and one uppercase letter? Thanks in advance

I am doing like this

function validate_pass{
var var_password = document.getElementById("npassword").value;
else if (!(/^(?=.*\d)(?=.*[A-Z]).+$/).test(var_password))){
    msg = "Password should contain atleast.";

    showErrorMsgPassword(msg);
    $('#npassword').val('');
    $('#cpassword').val('');
    return false;
  }

else return true;

Answer 1

If the desire is to test a string to see if it has a least one digit and at least one uppercase letter in any order and with any other characters allowed too, then this will work:

var str = "abc32Qdef";
var re = /[A-Z].*\d|\d.*[A-Z]/;
var good = re.test(str);​

Working demo with a bunch of test cases here: http://jsfiddle.net/jfriend00/gYEmC/

Answer 2

It's been a while since I've done this, and I'm fairly certain there is a more efficient way than this. You will need to use positive lookaheads, but there should be a way to remove the wildcards from within them:

This regex ( /^(?=.*[AZ])(?=.*\d).*$/ ) will return the entire password if it matches the criteria.

('a3sdasFf').match(/^(?=.*[AZ])(?=.*\d).*$/);

Answer 3

Like below:

/(\d.*[A-Z])|([A-Z].*\d)/

To test a string matched or not:

var str = "abc32dQef";
var is_matched = /(\d.*[A-Z])|([A-Z].*\d)/.test(str);