JavaScript 匿名 Function 带有来自 Call() 的参数

Question

I am trying to do the following:

function main(callback) {
   $.ajax('server-side', function() {
       this.callback.call("hello");
   }.bind({ callback: callback });
}

main(function(response) {
   alert(response);
});

Response is undefined , I would expect it to be "hello" . Any ideas why?

Answer 1

call first argument should be a reference to "this". Being "this" the context where you want to execute your function. Call function Mozila MDN

Answer 2

You wrote:

function main(callback) {
   $.ajax('server-side', function() {
       this.callback.call("hello");
   }.bind({ callback: callback });
}

main(function(response) {
   print response;
});

print doesnt exists in javascript.

then you wrote this.callback.call, which is wrong

you should write

callback.call(this,"hello") , 

just check the call function signature.