在 Java 中将字符串转换为“字符”数组

Question

I want to convert a String to an array of objects of Character class but I am unable to perform the conversion. I know that I can convert a String to an array of primitive datatype type "char" with the toCharArray() method but it doesn't help in converting a String to an array of objects of Character type.

How would I go about doing so?

Answer 1

Use this:

String str = "testString";
char[] charArray = str.toCharArray();
Character[] charObjectArray = ArrayUtils.toObject(charArray);

Answer 2

One liner with java-8 :

String str = "testString";

//[t, e, s, t, S, t, r, i, n, g]
Character[] charObjectArray = 
    str.chars().mapToObj(c -> (char)c).toArray(Character[]::new); 

What it does is:

• get an IntStream of the characters (you may want to also look at codePoints() )
• map each 'character' value to Character (you need to cast to actually say that its really a char , and then Java will box it automatically to Character )
• get the resulting array by calling toArray()

Answer 3

Why not write a little method yourself

public Character[] toCharacterArray( String s ) {

   if ( s == null ) {
     return null;
   }

   int len = s.length();
   Character[] array = new Character[len];
   for (int i = 0; i < len ; i++) {
      /* 
      Character(char) is deprecated since Java SE 9 & JDK 9
      Link: https://docs.oracle.com/javase/9/docs/api/java/lang/Character.html
      array[i] = new Character(s.charAt(i));
      */
      array[i] = s.charAt(i);
   }

   return array;
}

Answer 4

Converting String to Character Array and then Converting Character array back to String

   //Givent String
   String given = "asdcbsdcagfsdbgdfanfghbsfdab";

   //Converting String to Character Array(It's an inbuild method of a String)
   char[] characterArray = given.toCharArray();
   //returns = [a, s, d, c, b, s, d, c, a, g, f, s, d, b, g, d, f, a, n, f, g, h, b, s, f, d, a, b]

//ONE WAY: Converting back Character array to String

  int length = Arrays.toString(characterArray).replaceAll("[, ]","").length();

  //First Way to get the string back
  Arrays.toString(characterArray).replaceAll("[, ]","").substring(1,length-1)
  //returns asdcbsdcagfsdbgdfanfghbsfdab
  or 
  // Second way to get the string back
  Arrays.toString(characterArray).replaceAll("[, ]","").replace("[","").replace("]",""))
 //returns asdcbsdcagfsdbgdfanfghbsfdab

//Second WAY: Converting back Character array to String

String.valueOf(characterArray);

//Third WAY: Converting back Character array to String

Arrays.stream(characterArray)
           .mapToObj(i -> (char)i)
           .collect(Collectors.joining());

Converting string to Character Array

Character[] charObjectArray =
                           givenString.chars().
                               mapToObj(c -> (char)c).
                               toArray(Character[]::new);

Converting char array to Character Array

 String givenString = "MyNameIsArpan";
char[] givenchararray = givenString.toCharArray();


     String.valueOf(givenchararray).chars().mapToObj(c -> 
                         (char)c).toArray(Character[]::new);

benefits of Converting char Array to Character Array you can use the Arrays.stream funtion to get the sub array

String subStringFromCharacterArray = 

              Arrays.stream(charObjectArray,2,6).
                          map(String::valueOf).
                          collect(Collectors.joining());

Answer 5

You have to write your own method in this case. Use a loop and get each character using charAt(i) and set it to your Character[] array using arrayname[i] = string.charAt[i] .

Answer 6

String#toCharArray returns an array of char , what you have is an array of Character . In most cases it doesn't matter if you use char or Character as there is autoboxing . The problem in your case is that arrays are not autoboxed, I suggest you use an array of char ( char[] ).

Answer 7

I hope the code below will help you.

String s="Welcome to Java Programming";
char arr[]=s.toCharArray();
for(int i=0;i<arr.length;i++){
    System.out.println("Data at ["+i+"]="+arr[i]);
}

It's working and the output is:

Data at [0]=W
Data at [1]=e
Data at [2]=l
Data at [3]=c
Data at [4]=o
Data at [5]=m
Data at [6]=e
Data at [7]= 
Data at [8]=t
Data at [9]=o
Data at [10]= 
Data at [11]=J
Data at [12]=a
Data at [13]=v
Data at [14]=a
Data at [15]= 
Data at [16]=P
Data at [17]=r
Data at [18]=o
Data at [19]=g
Data at [20]=r
Data at [21]=a
Data at [22]=m
Data at [23]=m
Data at [24]=i
Data at [25]=n
Data at [26]=g

Answer 8

another way to do it.

String str="I am a good boy";
    char[] chars=str.toCharArray();

    Character[] characters=new Character[chars.length];
    for (int i = 0; i < chars.length; i++) {
        characters[i]=chars[i];
        System.out.println(chars[i]);
    }

Answer 9

This method take String as a argument and return the Character Array

/**
 * @param sourceString
 *            :String as argument
 * @return CharcterArray
 */
public static Character[] toCharacterArray(String sourceString) {
    char[] charArrays = new char[sourceString.length()];
    charArrays = sourceString.toCharArray();
    Character[] characterArray = new Character[charArrays.length];
    for (int i = 0; i < charArrays.length; i++) {
        characterArray[i] = charArrays[i];
    }
    return characterArray;
}

Answer 10

if you are working with JTextField then it can be helpfull..

public JTextField display;
String number=e.getActionCommand();

display.setText(display.getText()+number);

ch=number.toCharArray();
for( int i=0; i<ch.length; i++)
    System.out.println("in array a1= "+ch[i]);

Answer 11

chaining is always best:D

String str = "somethingPutHere";
Character[] c = ArrayUtils.toObject(str.toCharArray());

Answer 12

If you don't want to rely on third party API's, here is a working code for JDK7 or below. I am not instantiating temporary Character Objects as done by other solutions above. foreach loops are more readable, see yourself:)

public static Character[] convertStringToCharacterArray(String str) {
    if (str == null || str.isEmpty()) {
        return null;
    }
    char[] c = str.toCharArray();
    final int len = c.length;
    int counter = 0;
    final Character[] result = new Character[len];
    while (len > counter) {
        for (char ch : c) {
            result[counter++] = ch;
        }
    }
    return result;
}

Answer 13

I used the StringReader class in java.io . One of it's functions read(char[] cbuf) reads a string's contents into an array.

String str = "hello";
char[] array = new char[str.length()];
StringReader read = new StringReader(str);

try {
    read.read(array); //Reads string into the array. Throws IOException
} catch (IOException e) {
    e.printStackTrace();
}

for (int i = 0; i < str.length(); i++) {
        System.out.println("array["+i+"] = "+array[i]);
}

Running this gives you the output:

array[0] = h
array[1] = e
array[2] = l
array[3] = l
array[4] = o

Answer 14

---

String[] arr = { "abc", "cba", "dac", "cda" };
    Map<Character, Integer> map = new HashMap<>();
    String string = new String();
    for (String a : arr) {
        string = string.concat(a);

    }
    System.out.println(string);

    for (int i = 0; i < string.length(); i++) {
        if (map.containsKey(string.charAt(i))) {
            map.put(string.charAt(i), map.get(string.charAt(i)) + 1);

        } else {
            map.put(string.charAt(i), 1);

        }
    }
    System.out.println(map);

//out put {a=4, b=2, c=4, d=2}