Shell 脚本无法将文件数据传递给 shell 输入

Question

cal April 2012 | cat > t | cat < t | more

Why does it showing nothing? Why isn't it showing

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Answer 1

| (anonymous pipe) connects stdout ( 1 ) of the first process with stdin ( 0 ) of the second. After redirecting the output to a file, there is no stdout left, so there's nothing to pipe. Also, cat | cat < file cat | cat < file does not really make sense, it gets two inputs connected to stdin (at least with bash, redirection comes later and "wins": echo uiae | cat <somefile will output the content of somefile)

If you want to display output of a command and, at the same time, write it to the file, use the tee binary. It writes to a file, but still writes to stdout

cal April 2012 | tee t | more
cat t # content of the above `cal` command

Answer 2

Because that first cat > t sends all its output to a file called t , leaving no more for the pipeline.

If your intent is to send it to a file and through more to the terminal, just use:

cal April 2012 | tee t | more

This | cat < t | cat < t construct is very strange and I'm not even sure if it would work. It's trying to connect two totally different things to the standard input of cat and certainly unnecessary.

Answer 3

this works for me if there's no existing file named t in the current directory. I'm using bash on Ubuntu Oneiric.

$ cal April 2012 | cat > t | cat < t | more
 April 2012       
 Su Mo Tu We Th Fr Sa  
 1  2  3  4  5  6  7  
 8  9 10 11 12 13 14  
 15 16 17 18 19 20 21  
 22 23 24 25 26 27 28  
 29 30
$ cal April 2012 | cat > t | cat < t | more
$ rm t
$ cal April 2012 | cat > t | cat < t | more
 April 2012       
 Su Mo Tu We Th Fr Sa  
 1  2  3  4  5  6  7  
 8  9 10 11 12 13 14  
 15 16 17 18 19 20 21  
 22 23 24 25 26 27 28  
 29 30