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字典作为表在 Django 模板

[英]Dictionary As Table In Django Template

I have a dictionary:我有一本字典:

field = 

{
   u'Birthday:': [datetime.date(2012, 4, 6), datetime.date(2012, 4, 27)],
   u'Education': [u'A1', u'A2'],
   u'Job:': [u'job1', u'job2'],
   u'Child Sex:': [u'M', u'F']
}

My template code is:我的模板代码是:

<table width="100%" border="0">
     <tr>
        {% for k, v in field.items %}
            <th>{{ k }}</th>
        {% endfor %}
     </tr>
     <tr>
       {% for k,v in field.items %}
            <td>
                <table width="100%" border="0">
                 {% for a in v %}
                     <tr class="{% cycle 'odd' 'even' %}"><td>{{ a }}</td></tr>
                 {% endfor %}
                </table>
            </td>
        {% endfor %}
     </tr>
</table>

I want to show dictionary keys as table headers and esach value as row:我想将字典键显示为表头,将 esach 值显示为行:

Birthday                          Education      Job        Child Sex
datetime.date(2012, 4, 6)         A1             job1       M
datetime.date(2012, 4, 27)        A2             job2       F

But I have to insert a second table.但我必须插入第二张表。 Is there any way toshow dictionary keys as table headers and esach value as rows?有什么方法可以将字典键显示为表头,将 esach 值显示为行?

Thanks in advance提前致谢

You can make the template code a lot easier to read if you provide the data as a table in your dictionary.如果将数据作为字典中的表格提供,则可以使模板代码更易于阅读。 It would look more like this:它看起来更像这样:

field = {
    'headers': [u'Birthday:', u'Education', u'Job', u'Child Sex'],
    'rows': [[datetime.date(2012, 4, 6), u'A1', u'job1', u'M']
            ,[datetime.date(2012, 4, 27), u'A2', u'job2', u'F']]
}

You can now iterate over the headers as follows:您现在可以按如下方式遍历标题:

<tr>
{% for header in field.headers %}
    <th>{{ header }}</th>
{% endfor %}
</tr>

And each row can be displayed using:每行都可以使用以下方式显示:

<tr>    
{% for value in field.rows %}
    <td>{{ value }}</td>
{% endfor %}
</tr>

Now, you can obtain the 'headers' value using field.keys() :现在,您可以使用field.keys()获取'headers'值:

[u'Birthday:', u'Education', u'Job:', u'Child Sex:']

You can get the 'values' using the following loop (where 2 is the number of rows):您可以使用以下循环获取'values' (其中2是行数):

rows = []
for i in xrange(2):
    row = []
    for k in field.keys():
        row.append(field[k][i])
    rows.append(row)

Or as a one-liner:或者作为单线:

rows = [[field[k][i] for k in field.keys()] for i in xrange(2)]

Simeon's answer worked for me, but I had to do something a little different int the template to get the rows and data looking right because of the nested list: Simeon 的回答对我有用,但由于嵌套列表,我不得不在模板中做一些不同的事情以使行和数据看起来正确:

        {% for row in field.rows %}
            <tr>
                {% for value in row %}
                    <td>{{value}}</td>
                {% endfor %}
            </tr>
        {% endfor %}

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