如何发布选中的单选按钮

Question

i have a jsfiddle here . What it does is that when the user clicks on the "Add Question" button, it adds a radio buttons in each row. But what I want to do is use $_POST to post selected radio buttons in each row into the the insertQuestions.php page (action the form takes use to).

So what I want to know is how do I write the $_POST statement to be able to paste checked radio buttons?

UPDATE:

Is this code below correct in terms of finding the ReplyId for the selected radio by using z case statement then a query:

$i = 0;
$c = count($_POST['reply']);

$insertquestion = array();

for($i = 0;  $i < $c; $i++ ){

    switch ($_POST['reply'][$i]){

    case "Single": 
    $selected_option = "Single";
    break;

    case "Multiple": 
    $selected_option = "Multiple";
    break;

    default:
    $selected_option = "";
    break;

    }      


    $replyquery = "SELECT ReplyId FROM Reply WHERE (ReplyType = '". mysql_real_escape_string($_POST['reply'])."')";
    $replyrs = mysql_query($replyquery);
    $replyrecord = mysql_fetch_array($replyrs);
    $replyid = $replyrecord['ReplyId']; 

Answer 1

All you need to do is when you run your AJAX script. On the process page you would use something like

<?PHP
$reply1 = $_POST['reply1'];
$reply2 = $_POST['reply2'];

however you will want to change the name of the input fields to name="reply[]" which will make the posted data an array

UPDATE: The previous is only valid for checkboxes in this case (which there are none) With checkboxes of the same name, is checkbox 1 is checked and then checkbox 2 is checked, you will only get the value of checkbox 2 on the post.

Since reply is the name with a number after for duplicated questions, you can always get all posted variables by just using $_POST . Doing this will give you an array of ALL posted data

If you want to go through each reply since it is dynamic just do a foreach statement

foreach($_POST as $k=>$v) {
    //Run script to process each posted reply 
}