汇编，将ascii值存储到寄存器中

Question

How would I store 8 ascii values into a register or a variable? For instance I have these values in ascii 30 30 34 20 33 32 32 00

Which would be 004 322

80x86 architecture

Answer 1

mov eax 30303420
mov ebx 33323200

or you can do in the data segment

var db 30 , 30 ,34 ,20 ,33 ,32 ,32, 00

you can use the stack(LIFO) as well:

mov eax 30303420
mov ebx 33323200
push ebx
push eax

or to one register 8 byte = 8*8 bit = 64 bit:

mov rax 3030342033323200h

EDIT:

extern  printf      ; the C function, to be called

SECTION .data       ; Data section, initialized variables

a:  db  30 , 30 ,34 ,20 ,33 ,32 ,32, 00 
fmt:    db "a=%s",'0'


SECTION .text                   ; Code section.

global main     ; the standard gcc entry point
main:               ; the program label for the entry point
push    ebp     ; set up stack frame
mov     ebp,esp

push    a           ; value of variable a
push    fmt
call    printf      ; Call C function
add     esp, 8      ; maybe I missed some bytes here 

mov     esp, ebp    ; takedown stack frame
pop     ebp     ; same as "leave" op

mov eax,0       ;  normal, no error, return value
ret         ; return

Answer 2

Why not use the stack? Especially if the values are not constants

EDIT: woops might need some adjustment for 32-bit words :)

; load values
PUSH 30
PUSH 30
PUSH 34
PUSH 20
PUSH 33
PUSH 32
PUSH 32
PUSH 0

; do stuff
; [ESP] = 0  (last value)
; [ESP+7] = 30  (first value)

; restore stack pointer  ("free memory")
SUB ESP, 8