当路径在PHP中包含空格时，scandir或opendir不起作用

Question

The following functions does not work when there is space in the directory path. For example, in the following path directory name is 'Stack Overflow_files' which contains a space.

 $dir = '/home/mamun/workspace/barj/barj/barj/Sequence/Stack Overflow_files';
 $scanned_directory =  array_diff(scandir($dir, 0), array('..', '.'))

or

$dh  = opendir($dir);
while (false !== ($filename = readdir($dh))) {
         $scanned_directory[] = $filename;
}

I can find the solution from the terminal running ls '$dir' . but is there any way in php to get the dirctory listing?

Answer 1

Alternative solution

 $URL = str_replace("\ ","%20","../pasta1/pasta com espaco/pasta2");<br>
 $arquivos = scandir($URL);

<br>

 echo $arquiovos[0];<br>
 echo $arquiovos[1];<br>

Answer 2

尝试用反斜杠逃离空间 -

$dir = '/home/mamun/workspace/barj/barj/barj/Sequence/Stack\ Overflow_files';

Answer 3

Try urlencoding. The directory path May be like

         $dir = '/home/mamun/workspace/barj/barj/barj/Sequence/Stack%20Overflow_files';

Answer 4

尝试

$dir = urlencode('/home/mamun/workspace/barj/barj/barj/Sequence/Stack Overflow_files');

Answer 5

Bro this is the final solution

$path="/var/www/images";
$dir="folder with space";
$files=scandir("${path}/${dir}");

And bingo