[英]Python:How do I use “or” in a regular expression?
I have the text below : 我有以下文字:
text='apples and oranges apples and grapes apples and lemons'
and I want to use regular expressions to achieve something like below: 而且我想使用正则表达式来实现如下所示:
'apples and oranges' 苹果和橘子
'apples and lemons' 苹果和柠檬
I tried this re.findall('apples and (oranges|lemons)',text)
, but it doesn't work. 我尝试了这个re.findall('apples and (oranges|lemons)',text)
,但是它不起作用。
Update: If the 'oranges' and 'lemons' were a list : new_list=['oranges','lemons']
, how could I go to (?:'oranges'|'lemons') without typing them again ? 更新:如果'oranges'和'lemons'是一个列表: new_list=['oranges','lemons']
,我怎么能不用再次输入而转到(?:'oranges'|'lemons')?
Any ideas? 有任何想法吗? Thanks. 谢谢。
re.findall()
: If one or more groups are present in the pattern, return a list of groups; re.findall()
:如果模式中存在一个或多个组,则返回组列表;否则,返回一个列表。 this will be a list of tuples if the pattern has more than one group. 如果模式包含多个组,则这将是一个元组列表。
Try this: 尝试这个:
re.findall('apples and (?:oranges|lemons)',text)
(?:...)
is a non-capturing version of regular parentheses. (?:...)
是常规括号的非捕获版本。
What you've described should work: 您所描述的应该起作用:
In example.py: 在example.py中:
import re
pattern = 'apples and (oranges|lemons)'
text = "apples and oranges"
print re.findall(pattern, text)
text = "apples and lemons"
print re.findall(pattern, text)
text = "apples and chainsaws"
print re.findall(pattern, text)
Running python example.py
: 运行python example.py
:
['oranges']
['lemons']
[]
您是否尝试过非捕获组re.search('apples and (?:oranges|lemons)',text)
吗?
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