检查字符串是否等于x％

Question

I want to compare three strings:

"a text string" //target string
"a kind of similar text string"
"the cow jumps over the moon"

And set a percentage parameter that returns the results that are x% similar to the target.

$results = compare($array,$target,80)

$results // Returns an array with str 1,2, because they are at least 80 similar to the target.

Also, is a similar function possible in JavaScript or jQuery?

Answer 1

In PHP, there is the function similar_text . As for JavaScript, there's the PHP.js project , which re-implements PHP functions in JavaScript. They have an implementation of similar_text you can use.

The JavaScript implementation doesn't support the percent parameter, it seems.

Answer 2

The function you're looking for is similar_text .

It takes an optional 3rd parameter (passed by reference) where the percentage difference is placed.

In your situation, the following should do:

// Returns true if $str1 is at least $pct similar to $str2, otherwise false.
function compare($str1, $str2, $pct)
{
    $p = 0;
    similar_text($str1, $str2, $p);

    return ($p >= $pct);
}