Windows注册表，如何添加本机程序以执行启动？

Question

I have done my Native program for Windows.

( which, I've compiled with #pragma comment(linker, "/SUBSYSTEM:NATIVE" )).

I want to add my program to auto-executing list, how can I do it?

My exact questions are:

1). How can I do it in Windows Registry ( I have googled about BootExecute/SetupExecute table, but Setup is empty and BootExecute has only: *autocheck autochk ** ). So I was confused of empty tables ( cause , if it's empty, where are another auto-exec programs in Windows, which ntdll.dll does load ? )

2). Does it matter what is the version of the executable program: for 32/64 bits system ?

I have put it in %windir%\\system32 , but there is also %windir%\\WOW64 folder.

Should I highlight this detail in Registry or Windows loads each driver from both folders and just simply highlight them as *32 or 64 bits program in taskmgr?

3). Are there any other ways to do that?

Answer 1

1) You need to place it to BootExecute registry value. It's a multi-string value, and you need to keep whatever strings are already there (normally only "autocheck autochk *") and just append your program name with no extension.

2) You should compile 32 bit binary for 32 bit OS, and 64 bit binary for 64 bit OS. Binary should be placed into %windir%\\system32

3) That's the only way as far as I know

PS - for an example install any file system or registry defragmenter that has Boot Defrag feature, enable it, and see how it modifies BootExecute.