有没有一种方法可以将IOException抛出为可运行状态？

Question

I have some code thats not working(which is a common occurrence for me), but because I am not getting an errors it just continues to run with bad data. The problem I think is it keeps telling me to wrap parts of my code in try/catch blocks(my tests are basic, I just output a message in the try area and if it gets outputted I assume all went well. All does not seem well in my code). I understand in production, putting a try/catch statement helps the code to continue to run but its making me troubleshooting difficult because I'm trying to troubleshoot that section of my code.

Is there a way around this so I can actually see when something fails within the try area?

Here's a sample of my code:

    try {
        ByteArrayInputStream baos_back = new ByteArrayInputStream(message);
        ObjectInputStream oos_back = new ObjectInputStream(baos_back);
        i = oos_back.readInt();
        d = oos_back.readDouble();
        list_of_ints = (int[]) oos_back.readObject();
        oos_back.reset();
        baos_back.reset();
    } catch (ClassNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

Answer 1

Are you trying to get your program to blow up when this error occurs? If so, you should be able to wrap your IOException in a RuntimeException and throw that instead. They're unchecked, so you don't need to declare them and it should kill your program just fine.

Answer 2

If you want your code to throw the appropriate exception, I'd suggest not using try-catch blocks at all. Try-catch is used to handle exceptions as they arise and then keep running the program, but it sounds like you don't want to handle them at all.

If you do want to use try-catch blocks you could always manually throw a RuntimeException at the end of the catch block. Something like:

throw new IOException();
try {
    // Some code...
} catch(Exception e) {
    // Error handling code...
    throw new RuntimeException(e.getMessage());
}

Answer 3

As I mentioned in my comment, you can catch all exceptions in Java with a blanket catch statement:

try {
    // code
} catch (Exception e) {
    e.printStackTrace();
}

This will catch every Exception thrown in the try block, and the only things it won't catch are Error s.

In practice, you will want to limit the types of exceptions you catch, and catch more specific exceptions, so you can exception chain as follows:

try {
    // code
} catch (IOException ioe) {
    // we expected this
    ioe.printStackTrace();
} catch (SomeOtherException soe) { // just an example...
    soe.printStackTrace();
} catch (Exception e) {
    // Did we expect this? Maybe not!
    e.printStackTrace();
}

The above also makes it known that you expect some types of exceptions to occur, and then a big blanket catch-all statement that might catch things you didn't expect.

You can also log exceptions to a file or something else, rather than output them to standard out as this code does right now. A basic logging utility is java.util.logging .

---

I still recommend learning to use a debugger though. Debuggers can do a lot of things like halt program execution whenever an exception is thrown, and allow you to inspect the values of variables and fields at any point in the program's execution. If you use Eclipse or Netbeans or IntelliJ or other IDEs, they have debuggers. If you use the command line, there is the jdb command-line java debugger.

Answer 4

I suggest editing your code generation template to do this

catch ( $ExceptionClass e )
{
  // TODO: Autogenerated catch block
  e.printStackTrace();
  throw new RuntimeExcepton( e );
}

This way you have a TODO reminder, a barf on stdout, and are ensured that your program will blow up if you do not provide correct exception handler.