[英]C# Convert a number larger than Int64 to HexaDecimal
I am trying to convert a big number(ex: 9407524828459565063) to Hexadecimal(ex: 828E3DFD00000000) in C#. 我想在C#中将一个大数字(例如:9407524828459565063)转换为十六进制(例如:828E3DFD00000000)。
The problem is that the number is larger than Int64's max value. 问题是该数字大于Int64的最大值。
i looked up everywhere and couldn't find a working solution. 我到处查找,找不到合适的解决方案。
Any help over here? 有什么帮助吗?
Thank you. 谢谢。
I would use the System.Numerics.BigInteger class to do this. 我会使用System.Numerics.BigInteger类来执行此操作。 The exact solution depends on the format in which you have this number: string, double, other.
确切的解决方案取决于您具有此数字的格式:字符串,双精度,其他。
If string ( s
): 如果string(
s
):
var bigInt = BigInteger.Parse(s);
var hexString = bigInt.ToString("x");
If double ( d
): 如果加倍(
d
):
var bigInt = new BigInteger(d);
var hexString = bigInt.ToString("x");
... etcetera. ......等等。
Perhaps: 也许:
BigInteger b = 9407524828459565063;
var hex = b.ToString("X2");
Or 要么
ulong l = 9407524828459565063;
var hex = l.ToString("X2");
If you are using .NET 4.0, you might have a look at the BigInteger class: 如果您使用的是.NET 4.0,则可以查看BigInteger类:
http://msdn.microsoft.com/en-us/library/system.numerics.biginteger.aspx http://msdn.microsoft.com/en-us/library/system.numerics.biginteger.aspx
BigInteger bi = new BigInteger();
bi = 9407524828459565063;
string bix = bi.ToString("X");
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