Windows 窗体 - 输入按键激活提交按钮？

Question

如何在表单上的任何位置捕获输入按键并强制它触发提交按钮事件？

Answer 1

If you set your Form 's AcceptButton property to one of the Button s on the Form , you'll get that behaviour by default.

Otherwise, set the KeyPreview property to true on the Form and handle its KeyDown event. You can check for the Enter key and take the necessary action.

Answer 2

private void textBox_KeyDown(object sender, KeyEventArgs e) 
{
    if (e.KeyCode == Keys.Enter)
        button.PerformClick();
}

Answer 3

You can designate a button as the "AcceptButton" in the Form's properties and that will catch any "Enter" keypresses on the form and route them to that control.

See How to: Designate a Windows Forms Button as the Accept Button Using the Designer and note the few exceptions it outlines (multi-line text-boxes, etc.)

Answer 4

如前所述，将表单的AcceptButton属性设置为其按钮之一并将该按钮的DialogResult属性设置为DialogResult.OK ，以便调用者知道对话框是被接受还是被解除。

Answer 5

You can subscribe to the KeyUp event of the TextBox .

private void txtInput_KeyUp(object sender, KeyEventArgs e)
{
    if (e.KeyCode == Keys.Enter)
       DoSomething();
}

Answer 6

表单有一个KeyPreview属性，您可以使用它来拦截按键。

Answer 7

Simply use

this.Form.DefaultButton = MyButton.UniqueID;  

**Put your button id in place of 'MyButton'.

Answer 8

Set the KeyPreview attribute on your form to True, then use the KeyPress event at your form level to detect the Enter key. On detection call whatever code you would have for the "submit" button.

Answer 9

  if (e.KeyCode.ToString() == "Return")
  { 
      //do something
  }