我想在他们登录后显示在线用户
[英]I want to display the online user when they have logged on
问题描述
I would like to display: Logged in as: _ __ _ ___ 
我想显示：登录为： _ __ _ ___
The code so far: 到目前为止的代码：
The login check, 登录检查，
<?php
include('config.php');
// username and password sent from form
$myemail=$_POST['myemail'];
$mypassword=$_POST['mypassword'];
// To protect MySQL injection
$myemail = stripslashes($myemail);
$mypassword = stripslashes($mypassword);
$myemail = mysql_real_escape_string($myemail);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE email='$myemail' and password='$mypassword'";
$result=mysql_query($sql);
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
if($count==1){
session_start();
$_SESSION['myemail'] = $myemail;
header("Location: http://www.jblanksby.yourwebsolution.net/login_success.php? user=$myemail"); }
else
{ header("Location: http://www.jblanksby.yourwebsolution.net/loginerror.php");
}
?>
The login success page/first members page, 登录成功页面/第一个成员页面，
<?
$email = $_GET['myemail'];
session_start();
$_SESSION['myemail'] = $email;
if(isset($_SESSION['email'])){
} else {
echo "
<script language='javascript'>
alert('Sorry, but you must login to view the members area!')
</script>
<script>
window.location='http://jblanksby.yourwebsolution.net/sign_in.php'
</script>
"; }
?>
<html>
blah blah blah
</html>
The code used to display the users email, 用于显示用户电子邮件的代码，
Logged in as: <? echo "$email"; ?>
The log in side of things is perfect. 登录方面的事情是完美的。 Just displaying the users email is proving difficult. 仅显示用户电子邮件证明是困难的。 What have I done wrong/missed out? 我做错了什么/错过了什么？
3 个解决方案
解决方案1
1 2012-04-20 00:01:17
Since you are trying to display values out from the session, you have to use $_SESSION['email'] . 由于您尝试从会话中显示值，因此必须使用$_SESSION['email'] 。
session_start(); // Or, if you have done it ahead, then omit this
echo "Logged in as:".$_SESSION['email'];
解决方案2
1 2012-04-20 00:17:48
Use Starx suggestion on the $_SESSION but you need to move your session_start as the first line of PHP on the page, above $email = $_GET['myemail']; 在$_SESSION上使用Starx建议，但你需要将session_start作为页面上的第一行PHP移动，在$email = $_GET['myemail']; (or $email = $_SESSION['email'] ) （或$email = $_SESSION['email'] ）
<?php
session_start();
$email = $_SESSION['email'];
?>
ADDED 添加
To use the session variable, declare it like so (assuming you are using a method=post on form submittal): 要使用会话变量，请将其声明为（假设您在表单提交时使用method = post）：
<?php
session_start();
$_SESSION['email'] = $_POST['email'];
?>
This of course isn't safe for user input, it's presumed that you are sanatizing the user input prior to passing it from page to page and injecting it into your queries, this is just a simple example. 这当然对于用户输入是不安全的，假设您在将用户输入从一个页面传递到另一个页面并将其注入查询之前对其进行了静态处理，这只是一个简单的示例。
解决方案3
0 2012-04-20 00:35:25
Login Script: 登录脚本：
$username = $_POST['username'];
$password = $_POST['password'];
$password = sha1($password);
if ($username&&$password) {
require_once('../db/nstDBconnector.php');
$qr = "SELECT * FROM `users` WHERE `username` = '$username'";
$query = mysql_query($qr);
$numrows = mysql_num_rows($query);
if ($numrows!=0) {
// check password against the password in the database
while ($row = mysql_fetch_array($query, MYSQL_ASSOC)) {
$storedUsername = $row['username'];
$storedPassword = $row['password'];
$storedUserType = $row['user_type'];
$storedUserFName = $row['full_name'];
$_SESSION['last_ip'] = $_SERVER['REMOTE_ADDR'];
}
// check to see if username and password match
if ($username==$storedUsername&&$password==$storedPassword) {
ob_start();
session_start();
$_SESSION['username'] = $storedUsername;
$_SESSION['user_type'] = $storedUserType;
$_SESSION['full_name'] = $storedUserFName;
header ('Location: main.php?login=successful');
} else {
header ('Location: index.php?error=incorrectPassword');
}
} else {
header ('Location: index.php?error=noUser');
}
} else {
header ('Location: index.php?error=missingUserAndPass');
}
The page you are taking them to after login: 登录后您带他们去的页面：
if ($_SESSION['username']) {
$userLogged = $_SESSION['username'];
$userType = $_SESSION['user_type'];
$userFName = $_SESSION['full_name'];
} else {
header ('Location: http://www.yourdomain.com/index.php?error=notLoggedIn');
}
Where you want to show user name on the page: 您要在页面上显示用户名的位置：
Logged in as <?php echo $userFName; ?>.
or 要么
echo "Logged in as ", $userFName, ".";
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