为什么Eclipse在返回后总是给我一个错误；

Question

I have some problem with eclipse android.

I have some java files, but if I call a method after return; (see the example) it tells me to remove the method. Why? I'm using Android 1.6.

public void onClick(View paramView)
 {
  switch (paramView.getId())
{
default:
case 2131296257:
}
while (true)
{
  return;
  fetchAlarmSettings();  <-- It tells me to remove this.
  if (this.strAlarmOnOff.equals("0"))
  {
    this.butAlarmSet.setText("Turn Alarm Off");
    this.db.updateSetting("alarmTime", this.strHour.concat(this.strMinute));
    this.db.updateSetting("alarmOnOff", "1");
    switch (this.cal.compareTo(Calendar.getInstance()))
    {
    default:
    case -1:
    }
    while (true)
    {
      this.setNotifications.setAlarm(this.cal);
      break;
      this.cal.roll(5, 1);
    }
  }
  this.butAlarmSet.setText("Turn Alarm On");
  this.db.updateSetting("alarmOnOff", "0");
  this.setNotifications.turnAlarmOff();
}
 }

Thanks!

Answer 1

Your method will stop running the moment that the return statement is hit. Basically it should give you an ' Unreachable code! ' warning, since any code after the return statement will never be executed. Removing the return keyword should fix the problem.

So basically Eclipse is telling you to remove the next line after the return since it will never be executed. If you remove the method call it will complain over what ever line you throw in next.

Besides that, there are other (according to me) flaws with your code... having a while(true) loop without a break condition in this case seems odd (but then again I might be wrong here). Also, the default block is usually found at the end of a series of case statements. Your second while(true) loop will only iterate once since once the this.setNotifications.setAlarm(this.cal); is executed the loop will stop iterating due to the break statement.

Answer 2

Eclipse will not allow you to write obsolute code, actually the IDE uses java compiler for that.

In this case the code below the return in certain branch (meaning that you can have return in the if and after it code for the else ) is not reachable and thus you get compile error.

Answer 3

简单的答案，您不能在“ return”语句之后执行任何操作。